Question

What is the maximum number of emission lines when the excited electron of H atom in n = 6 drops to the ground state?

Answer 1

Hint: There is a formula to calculate the number of spectral lines or emission lines formed by the electrons when it drops from orbit ‘n’ to ground state and it is as follows.
\[\text{Number of spectral lines = }\dfrac{n(n-1)}{2}\]
Where n = orbit from where the electron starts to drop to ground state.

Complete step by step answer:
- In the question it is given that an electron of hydrogen atom drops from n = 6 to ground state.
- We have to calculate the number of maximum spectral lines or emission lines that are going to be obtained when the electron drops from n = 6 to ground state.
- Means here n = 6.
- Substitute n value in the below formula to get the number of spectral lines formed.
\[\begin{align}
  & \text{Number of spectral lines = }\dfrac{n(n-1)}{2} \\
 & =\dfrac{6(6-1)}{2} \\
 & =15 \\
\end{align}\]
- Therefore the maximum number of emission lines formed when the excited electron of H atom in n = 6 drops to the ground state is 15.

- Means an electron forms 15 emission lines when it drops from n = 6 to ground level.

Note: When the electron drops from higher orbit to lower orbit means the electron losing or emitting energy then the electron forms some lines related to emitted energy then they are called as emission lines or spectral lines. When an electron jumps to a higher energy level then it absorbs some energy and forms an absorption spectrum or absorption spectral lines.