Maximum and minimum IP values in 3 d series are in:
A. Cr, Zn
B. Sc, Cu
C. Cu, Zn
D. Zn, Sc
Answer
589.5k+ views
Hint: ionization potential is the energy required for the removal of an electron from the outermost shell of an isolated gaseous atom. The atom having high charge density and small size require more energy to ionize. The atom having low charge density and large size require less energy to ionize.
Complete Step by step answer: Ionization potential is defined as the energy required for the removal of an electron from the outermost shell of an isolated gaseous atom. It is also known as ionization energy.
On going left to right in a period, the ionization potential increases.
The reason for increases in ionization potential is as follows:
-Increase in effective nuclear charge
-Decreases in size.
-Due to both of these factors, (increase in effective nuclear charge and decreases in size) the stabilization of the outermost shell increases, so it becomes hard to remove an electron from the outermost shell on going left to right in a period.
On going down in a group, the ionization potential decreases.
The reason for decreases in ionization potential is as follows:
-Decrease in effective nuclear charge
Increases in size.
-Due to both of these factors, (decrease in effective nuclear charge and increases in size) the stabilization of the outermost shell decreases, so it becomes easy to remove an electron from the outermost shell on going down in a group.
From left to right the $3$d series is shown as follows:
Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, Zn.
Scandium is the top left element of the $3d$ series so it has the largest size and minimum effective nuclear charge so it can lose electrons easily, so its IP is minimum.
Zinc is the top right element of $3$d series so it has the smallest size and maximum effective nuclear charge so it cannot lose electrons easily, so its IP is maximum.
Therefore, option (D) Zn, Sc is correct.
Note: On going left to right in a period, the electrons are added in the same shell and the proton number also increases, so the attraction of the nucleus on the outermost shell increases. So, the size of the atom decreases. On going down in a group, the electrons get added in the next higher shell so, the attraction of the nucleus on the outermost shell decreases so, the size of the atom increases.
Some elements disobey general trends such as nitrogen or alkaline earth metals due to fully-filled and half-filled electronic configuration.
Complete Step by step answer: Ionization potential is defined as the energy required for the removal of an electron from the outermost shell of an isolated gaseous atom. It is also known as ionization energy.
On going left to right in a period, the ionization potential increases.
The reason for increases in ionization potential is as follows:
-Increase in effective nuclear charge
-Decreases in size.
-Due to both of these factors, (increase in effective nuclear charge and decreases in size) the stabilization of the outermost shell increases, so it becomes hard to remove an electron from the outermost shell on going left to right in a period.
On going down in a group, the ionization potential decreases.
The reason for decreases in ionization potential is as follows:
-Decrease in effective nuclear charge
Increases in size.
-Due to both of these factors, (decrease in effective nuclear charge and increases in size) the stabilization of the outermost shell decreases, so it becomes easy to remove an electron from the outermost shell on going down in a group.
From left to right the $3$d series is shown as follows:
Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, Zn.
Scandium is the top left element of the $3d$ series so it has the largest size and minimum effective nuclear charge so it can lose electrons easily, so its IP is minimum.
Zinc is the top right element of $3$d series so it has the smallest size and maximum effective nuclear charge so it cannot lose electrons easily, so its IP is maximum.
Therefore, option (D) Zn, Sc is correct.
Note: On going left to right in a period, the electrons are added in the same shell and the proton number also increases, so the attraction of the nucleus on the outermost shell increases. So, the size of the atom decreases. On going down in a group, the electrons get added in the next higher shell so, the attraction of the nucleus on the outermost shell decreases so, the size of the atom increases.
Some elements disobey general trends such as nitrogen or alkaline earth metals due to fully-filled and half-filled electronic configuration.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

