
Match each of the set on the left in the roster form with the same set on the right described in set-builder form:
(i) \[\{ 1,2,3,6\} \] (a) {x: x is a prime number and a divisor of 6} (ii) \[\{ 2,3\} \] (b) {x: x is an odd natural number less than 10} (iii) \[\{ M,A,T,H,E,I,C,S\} \] (c) { x: x is natural number and divisor of 6} (iv) \[\{ 1,3,5,7,9\} \] (d) { x: x is a letter of the word MATHEMATICS}
| (i) \[\{ 1,2,3,6\} \] | (a) {x: x is a prime number and a divisor of 6} |
| (ii) \[\{ 2,3\} \] | (b) {x: x is an odd natural number less than 10} |
| (iii) \[\{ M,A,T,H,E,I,C,S\} \] | (c) { x: x is natural number and divisor of 6} |
| (iv) \[\{ 1,3,5,7,9\} \] | (d) { x: x is a letter of the word MATHEMATICS} |
Answer
576.6k+ views
Hint: Firstly we convert the set given in set-builder form to roaster form, and then we match the corresponding set-builder form to the roaster form given on the right side.
Complete step by step solution: Firstly we have,
a) {x: x is a prime number and a divisor of 6}
So, we have that 2 and 3 are prime numbers and they are a divisor of 6, so our set in roster form is \[\{ 2,3\} \]
Hence, we have that a) matches to ii).
b) {x: x is an odd natural number less than 10}
We, have 1,3,5,7,9 as odd natural numbers which are less than 10, so our set in roster form will be \[\{ 1,3,5,7,9\} \].
Hence, we have that b) matches to iv).
c) { x: x is natural number and divisor of 6}
So, 1,2,3,6 are the natural numbers and also divisor of 6, so our set in roster form will be, \[\{ 1,2,3,6\} \].
Hence, we have c) matches to i).
d) { x: x is a letter of the word MATHEMATICS}
Here, the letter of the word MATHEMATICS are M,A,T,H,E,I,C,S , So our set in roster form will be \[\{ M,A,T,H,E,I,C,S\} \].
Hence, we have d) matches to iii).
Note: Note: For a set to be properly defined it has to a well-defined collection of distinct objects. So every set we check out has a collection of distinct objects. In the set, \[\{ M, A, T, H, E, I, C, S \} \] we have, 8 elements whereas the word MATHEMATICS has 10 letters because few letters are repeating but as they are identical, we donโt consider them again in the set.
Complete step by step solution: Firstly we have,
a) {x: x is a prime number and a divisor of 6}
So, we have that 2 and 3 are prime numbers and they are a divisor of 6, so our set in roster form is \[\{ 2,3\} \]
Hence, we have that a) matches to ii).
b) {x: x is an odd natural number less than 10}
We, have 1,3,5,7,9 as odd natural numbers which are less than 10, so our set in roster form will be \[\{ 1,3,5,7,9\} \].
Hence, we have that b) matches to iv).
c) { x: x is natural number and divisor of 6}
So, 1,2,3,6 are the natural numbers and also divisor of 6, so our set in roster form will be, \[\{ 1,2,3,6\} \].
Hence, we have c) matches to i).
d) { x: x is a letter of the word MATHEMATICS}
Here, the letter of the word MATHEMATICS are M,A,T,H,E,I,C,S , So our set in roster form will be \[\{ M,A,T,H,E,I,C,S\} \].
Hence, we have d) matches to iii).
Note: Note: For a set to be properly defined it has to a well-defined collection of distinct objects. So every set we check out has a collection of distinct objects. In the set, \[\{ M, A, T, H, E, I, C, S \} \] we have, 8 elements whereas the word MATHEMATICS has 10 letters because few letters are repeating but as they are identical, we donโt consider them again in the set.
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Match each of the set on the left in the roster form with the same set on the right described in set-builder form:
| (i) \[\{ 1,2,3,6\} \] | (a) {x: x is a prime number and a divisor of 6} |
| (ii) \[\{ 2,3\} \] | (b) {x: x is an odd natural number less than 10} |
| (iii) \[\{ M,A,T,H,E,I,C,S\} \] | (c) { x: x is natural number and divisor of 6} |
| (iv) \[\{ 1,3,5,7,9\} \] | (d) { x: x is a letter of the word MATHEMATICS} |

Class 11 MATHS NCERT EXERCISE 1.1 (Question - 5) | Sets Class 11 Chapter 1 | NCERT | Ratan Kalra Sir
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