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Man X is standing in front of the plane mirror while man Y is running towards him from behind. If the man Y is running at a speed of 1ms1 , how many metres nearer does the manY seem to be away from man X after 5seconds ?
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(A) 7m
(B) 5m
(C) 6m
(D) 10m

Answer
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Hint :In this question, it is given that the man Y is running in front of the mirror. We know that in the case of the plane mirror, the object distance and the image distance will be the same. As the man X is stationary the velocity of the man Y with respect to him is the same as that with respect to the mirror.

Complete Step By Step Answer:
We know that for plane mirrors, the image distance is the same as the object distance but in the opposite direction.
Therefore, if we consider u as object distance and v as the image distance, we can say that
 |u|=|v|
As per the definition of velocity, it is the distance covered during the unit time.
 |dudt|=|dvdt|
Thus, the speed of image is equal to the speed of man Y.
As the man X is stationary, Hence, the speed of man Y with respect to man X will be 1ms1 .
Thus, we can say that the speed of image of man Y with respect to the man X is:
 1(1)=1+1=2ms1
The distance covered by the image of man Y with respect to man X in 5seconds will be : 2×5=10m .
Thus, the man Y seems to be 10m away from man X after 5seconds .
Hence, option D is the right answer.

Note :
Here, we have used the concept of the relative velocity. In the case of a plane mirror, we have seen that the velocities of the image and the object have the same magnitude. However the directions of these velocities are opposite.
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