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# Magnesium has atomic number 12. Write the number of electrons and protons that are present. What kind of ions will it form? Write the formula.

Last updated date: 20th Jun 2024
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Hint: Number of electrons and protons are equal to the atomic number of a neutral atom. Magnesium is an alkaline earth metal and so metals are electropositive in nature. Magnesium can easily lose two electrons to achieve the nearest noble gas configuration.

We know that metals are electropositive in nature. I.e, they can readily lose electrons from their valence shell. So, Magnesium has an electronic configuration of ${ \left[ Ne \right] { 3s }^{ 2 } }$ . So, by losing two electrons from its outermost ‘s’ subshell, it can attain the stable nearest noble gas configuration which is${ 1s }^{ 2 }{ 2s }^{ 2 }{ 2p }^{ 6 }$ .
So, Magnesium loses two electrons to form a positively charged ion, cation and its formula is ${ Mg }^{ 2+ }$ .
Therefore, we can conclude that the number of electrons and protons present in Magnesium is 12 and 12 respectively. And Magnesium forms a positively charged ion ,cation , whose formula is ${ Mg }^{ 2+ }$.