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# Lewis structure for :$ClO_3^-$ (chlorate ion)If the above Lewis structure is correct enter $1$ else enter $0$.

Last updated date: 14th Jul 2024
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Hint :For solving this problem, you should have the knowledge about polyatomic ion and oxidation number.Polyatomic ion is an ion containing more than one atom. Oxidation number is the number of electrons lost or gained by an element during a reaction.

Step-1 :
To solve the given problem, let’s determine the valence electron of all the atoms present in the compound.
Step-2 :
Here, we have given chocolate ions. So, know that the total charge on the ion should be $ClO_3^-$ . So, we know that the total charge on the ion should be $-1$ . We should first find the total valence electron. Here, chlorine has $1$ atom and contains $7$ electrons and oxygen atoms contain $18$ valence electrons.
So, total valence electron is :
$7+18-(-1)=26$
Step-3 :
Next we should find total electron pairs which is a sum of bond pairs and lone pairs. The total electron pairs can be calculated by dividing total valence electrons with $2$ . Here, dividing $26$ by $2$ , we get total electron pairs as $13$ .
Step-4 :
Here, chlorine is used as the central atom and oxygen as the surrounding atom. Here, maximum valency of chlorine is $7$ while that of oxygen is $2$ . So, oxygen can maximum from $2$ bonds while chlorine can form $7$ bonds. The charge on $1$ oxygen is $-1$ .

Note :
While determining the Lewis structure of a compound, the valence electron should be remembered and determined correctly so as to avoid any mistakes and if possible the Lewis structures of some basic compounds can be learned to simplify the process.