
Let z be a complex number such that $\left| z \right|+z=3+i$(where $i=\sqrt{-1}$). Then $\left| z \right|$ is equal to:-
A. $\dfrac{5}{4}$
B. $\dfrac{\sqrt{41}}{4}$
C. $\dfrac{\sqrt{34}}{3}$
D. $\dfrac{5}{3}$
Answer
507.9k+ views
Hint: We must assume z as a general complex number, $z=a+ib$ then the magnitude of the complex number $z$ will be $\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$using these two relations we must substitute them in the equation. By comparing real and imaginary parts we get value of $a$ and $b$.And finally we use these values to find $\left| z \right|$.
Complete step by step answer:
A complex number is the one which cannot be represented on a real number line alone so we also include a imaginary number line to collectively represent the number.
A complex number has two parts real part and a imaginary part as $z=a+ib$ $a,b\in \mathbb{R}$ (where $i=\sqrt{-1}$)
Where $a$ is called real part and $ib$ is complex part,
We have been given the following equation in the question,
$\left| z \right|+z=3+i$
We assume \[z\] as any general complex number to facilitate easy solving of question
Let $z=a+ib$,
The modulus or absolute value of any complex number is given by –
$\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$
Having all the necessary informations we will now substitute them in the given equation,
$\sqrt{{{a}^{2}}+{{b}^{2}}}+a+ib=3+i$
We will shift $a+ib$ to the right side,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3+i-(a+ib)$
Since we have only real number on left hand, we can write complex coefficient as 0.
$\sqrt{{{a}^{2}}+{{b}^{2}}}+0i=(3-a)+i(1-b)$
We compare the real and imaginary parts,
First we are comparing imaginary part,
$0i=i(1-b)$
$b=1$
Now we equate real parts,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Using \[b=1\]
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Squaring both sides,
${{a}^{2}}+1={{a}^{2}}+9-6a$
$a=\dfrac{4}{3}$
Since $\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$ we write,
\[\left| z \right|=\sqrt{1+{{\left( \dfrac{4}{3} \right)}^{2}}}\]
\[\left| z \right|=\sqrt{1+\dfrac{16}{9}}\]
\[\left| z \right|=\dfrac{5}{3}\]
So, the correct answer is “Option D”.
Note: We must take care that substitution is done properly, when comparing real and imaginary parts be sure to compare real part with real part and imaginary part with imaginary part. Students can also write \[a+ib\] as \[x+iy\] since change of variable doesn’t affect the number on the complex graph.
Complete step by step answer:
A complex number is the one which cannot be represented on a real number line alone so we also include a imaginary number line to collectively represent the number.
A complex number has two parts real part and a imaginary part as $z=a+ib$ $a,b\in \mathbb{R}$ (where $i=\sqrt{-1}$)
Where $a$ is called real part and $ib$ is complex part,
We have been given the following equation in the question,
$\left| z \right|+z=3+i$
We assume \[z\] as any general complex number to facilitate easy solving of question
Let $z=a+ib$,
The modulus or absolute value of any complex number is given by –
$\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$
Having all the necessary informations we will now substitute them in the given equation,
$\sqrt{{{a}^{2}}+{{b}^{2}}}+a+ib=3+i$
We will shift $a+ib$ to the right side,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3+i-(a+ib)$
Since we have only real number on left hand, we can write complex coefficient as 0.
$\sqrt{{{a}^{2}}+{{b}^{2}}}+0i=(3-a)+i(1-b)$
We compare the real and imaginary parts,
First we are comparing imaginary part,
$0i=i(1-b)$
$b=1$
Now we equate real parts,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Using \[b=1\]
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Squaring both sides,
${{a}^{2}}+1={{a}^{2}}+9-6a$
$a=\dfrac{4}{3}$
Since $\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$ we write,
\[\left| z \right|=\sqrt{1+{{\left( \dfrac{4}{3} \right)}^{2}}}\]
\[\left| z \right|=\sqrt{1+\dfrac{16}{9}}\]
\[\left| z \right|=\dfrac{5}{3}\]
So, the correct answer is “Option D”.
Note: We must take care that substitution is done properly, when comparing real and imaginary parts be sure to compare real part with real part and imaginary part with imaginary part. Students can also write \[a+ib\] as \[x+iy\] since change of variable doesn’t affect the number on the complex graph.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Explain why it is said like that Mock drill is use class 11 social science CBSE

The non protein part of an enzyme is a A Prosthetic class 11 biology CBSE

Which of the following blood vessels in the circulatory class 11 biology CBSE

What is a zygomorphic flower Give example class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

The deoxygenated blood from the hind limbs of the frog class 11 biology CBSE
