
Let z be a complex number such that $\left| z \right|+z=3+i$(where $i=\sqrt{-1}$). Then $\left| z \right|$ is equal to:-
A. $\dfrac{5}{4}$
B. $\dfrac{\sqrt{41}}{4}$
C. $\dfrac{\sqrt{34}}{3}$
D. $\dfrac{5}{3}$
Answer
572.4k+ views
Hint: We must assume z as a general complex number, $z=a+ib$ then the magnitude of the complex number $z$ will be $\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$using these two relations we must substitute them in the equation. By comparing real and imaginary parts we get value of $a$ and $b$.And finally we use these values to find $\left| z \right|$.
Complete step by step answer:
A complex number is the one which cannot be represented on a real number line alone so we also include a imaginary number line to collectively represent the number.
A complex number has two parts real part and a imaginary part as $z=a+ib$ $a,b\in \mathbb{R}$ (where $i=\sqrt{-1}$)
Where $a$ is called real part and $ib$ is complex part,
We have been given the following equation in the question,
$\left| z \right|+z=3+i$
We assume \[z\] as any general complex number to facilitate easy solving of question
Let $z=a+ib$,
The modulus or absolute value of any complex number is given by –
$\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$
Having all the necessary informations we will now substitute them in the given equation,
$\sqrt{{{a}^{2}}+{{b}^{2}}}+a+ib=3+i$
We will shift $a+ib$ to the right side,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3+i-(a+ib)$
Since we have only real number on left hand, we can write complex coefficient as 0.
$\sqrt{{{a}^{2}}+{{b}^{2}}}+0i=(3-a)+i(1-b)$
We compare the real and imaginary parts,
First we are comparing imaginary part,
$0i=i(1-b)$
$b=1$
Now we equate real parts,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Using \[b=1\]
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Squaring both sides,
${{a}^{2}}+1={{a}^{2}}+9-6a$
$a=\dfrac{4}{3}$
Since $\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$ we write,
\[\left| z \right|=\sqrt{1+{{\left( \dfrac{4}{3} \right)}^{2}}}\]
\[\left| z \right|=\sqrt{1+\dfrac{16}{9}}\]
\[\left| z \right|=\dfrac{5}{3}\]
So, the correct answer is “Option D”.
Note: We must take care that substitution is done properly, when comparing real and imaginary parts be sure to compare real part with real part and imaginary part with imaginary part. Students can also write \[a+ib\] as \[x+iy\] since change of variable doesn’t affect the number on the complex graph.
Complete step by step answer:
A complex number is the one which cannot be represented on a real number line alone so we also include a imaginary number line to collectively represent the number.
A complex number has two parts real part and a imaginary part as $z=a+ib$ $a,b\in \mathbb{R}$ (where $i=\sqrt{-1}$)
Where $a$ is called real part and $ib$ is complex part,
We have been given the following equation in the question,
$\left| z \right|+z=3+i$
We assume \[z\] as any general complex number to facilitate easy solving of question
Let $z=a+ib$,
The modulus or absolute value of any complex number is given by –
$\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$
Having all the necessary informations we will now substitute them in the given equation,
$\sqrt{{{a}^{2}}+{{b}^{2}}}+a+ib=3+i$
We will shift $a+ib$ to the right side,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3+i-(a+ib)$
Since we have only real number on left hand, we can write complex coefficient as 0.
$\sqrt{{{a}^{2}}+{{b}^{2}}}+0i=(3-a)+i(1-b)$
We compare the real and imaginary parts,
First we are comparing imaginary part,
$0i=i(1-b)$
$b=1$
Now we equate real parts,
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Using \[b=1\]
$\sqrt{{{a}^{2}}+{{b}^{2}}}=3-a$
Squaring both sides,
${{a}^{2}}+1={{a}^{2}}+9-6a$
$a=\dfrac{4}{3}$
Since $\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}$ we write,
\[\left| z \right|=\sqrt{1+{{\left( \dfrac{4}{3} \right)}^{2}}}\]
\[\left| z \right|=\sqrt{1+\dfrac{16}{9}}\]
\[\left| z \right|=\dfrac{5}{3}\]
So, the correct answer is “Option D”.
Note: We must take care that substitution is done properly, when comparing real and imaginary parts be sure to compare real part with real part and imaginary part with imaginary part. Students can also write \[a+ib\] as \[x+iy\] since change of variable doesn’t affect the number on the complex graph.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

