Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of S equal to,
$\left( a \right)$ 25
$\left( b \right)$ 34
$\left( c \right)$ 42
$\left( d \right)$ 41
Answer
658.8k+ views
Hint: In this particular question use the concept that total number of unordered pairs of disjoint subsets of any set containing n elements is equal to $\dfrac{{{3^n} + 1}}{2}$, so use these concepts to reach the solution of the question.
Complete step-by-step answer:
Given data:
S = {1, 2, 3, 4}
Now we have to find out the total number of unordered pairs of disjoint subsets of S.
Disjoint sets – Two sets are said to be disjoint sets if they have no elements in common i.e. the intersection of these sets is an empty set.
For example: A = {1, 2, 3} and B = {4, 5, 6}, so A, and B are called Disjoint sets.
Now we have to find out the total number of subsets of the given set S, such that the subsets are unordered pairs of disjoint subsets of S.
Now as we know that the total number of unordered pairs of disjoint subsets of any set containing n elements is equal to, N = $\dfrac{{{3^n} + 1}}{2}$.................... (1), where n = 1, 2, 3......
Now in the given subset number of elements is equal to 4, so n = 4.
Now substitute this value in equation (1) we have,
Therefore, N = $\dfrac{{{3^4} + 1}}{2}$
Now simplify this we have,
$ \Rightarrow N = \dfrac{{81 + 1}}{2} = \dfrac{{82}}{2} = 41$
So there are 41 unordered pairs of disjoint subsets of S.
So this is the required answer.
Hence option (d) is the correct answer.
Note: Whenever we face such types of questions the key concept we have to remember is that always recall that two sets are said to be a disjoint sets if they have no elements in common i.e. the intersection of these sets is an empty set, and always recall the formula to find out the total number of disjoint sets if a set contain n number of elements which is stated above.
Complete step-by-step answer:
Given data:
S = {1, 2, 3, 4}
Now we have to find out the total number of unordered pairs of disjoint subsets of S.
Disjoint sets – Two sets are said to be disjoint sets if they have no elements in common i.e. the intersection of these sets is an empty set.
For example: A = {1, 2, 3} and B = {4, 5, 6}, so A, and B are called Disjoint sets.
Now we have to find out the total number of subsets of the given set S, such that the subsets are unordered pairs of disjoint subsets of S.
Now as we know that the total number of unordered pairs of disjoint subsets of any set containing n elements is equal to, N = $\dfrac{{{3^n} + 1}}{2}$.................... (1), where n = 1, 2, 3......
Now in the given subset number of elements is equal to 4, so n = 4.
Now substitute this value in equation (1) we have,
Therefore, N = $\dfrac{{{3^4} + 1}}{2}$
Now simplify this we have,
$ \Rightarrow N = \dfrac{{81 + 1}}{2} = \dfrac{{82}}{2} = 41$
So there are 41 unordered pairs of disjoint subsets of S.
So this is the required answer.
Hence option (d) is the correct answer.
Note: Whenever we face such types of questions the key concept we have to remember is that always recall that two sets are said to be a disjoint sets if they have no elements in common i.e. the intersection of these sets is an empty set, and always recall the formula to find out the total number of disjoint sets if a set contain n number of elements which is stated above.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

