
What is $\left( {\dfrac{{\sec 18^\circ }}{{\sec 144^\circ }} + \dfrac{{\cos ec18^\circ }}{{\cos ec144^\circ }}} \right)$ equals to?
A. $\sec 18^\circ $
B.$\cos ec18^\circ $
C.-$\sec 18^\circ $
D.-$\cos ec18^\circ $
Answer
591.9k+ views
Hint: To find the value of the above expression we will break the 144 as 180 – 36. Then use the transformation of trigonometric ratio formula and simplify such that we will get the value of this expression.
Complete step-by-step answer:
First write 144 = 180 - 36 and proceed we will get,
$
= \left( {\dfrac{{\sec 18^\circ }}{{\sec \left( {180^\circ - 36^\circ } \right)}} + \dfrac{{\cos ec18^\circ }}{{\cos ec\left( {180^\circ - 36^\circ } \right)}}} \right) \\
= \left( {\dfrac{{\sec 18^\circ }}{{ - sec36^\circ }} + \dfrac{{\cos ec18^\circ }}{{\cos ec36^\circ }}} \right) \\
$
Now converting the above expression in the form of sin and cos
We will get,
$
= \left( { - \dfrac{{\dfrac{1}{{\cos 18^\circ }}}}{{\dfrac{1}{{\cos 36^\circ }}}} + \dfrac{{\dfrac{1}{{\sin 18^\circ }}}}{{\dfrac{1}{{\sin 36^\circ }}}}} \right) \\
= \left( { - \dfrac{{\cos 36^\circ }}{{\cos 18^\circ }} + \dfrac{{\sin 36^\circ }}{{\sin 18^\circ }}} \right) \\
$
On taking LCM and solving we get,
$ = \left( {\dfrac{{ - \cos 36^\circ \sin 18^\circ + \sin 36^\circ \cos 18^\circ }}{{\cos 18^\circ \sin 18^\circ }}} \right)$
Use the sin (A-B) formula then simplify we get,
$
= \left( {\dfrac{{\sin \left( {36^\circ - 18^\circ } \right)}}{{\cos 18^\circ \sin 18^\circ }}} \right) \\
= \left( {\dfrac{{\sin 18^\circ }}{{\cos 18^\circ \sin 18^\circ }}} \right) \\
= \dfrac{1}{{\cos 18^\circ }} \\
= \sec 18^\circ \\
$
The above expression is equals to $\sec 18^\circ $
So, the correct answer is “Option A”.
Note: Scientific calculators have sin, cos, and tan functions, as well as the inverse functions. It's worth taking a few minutes to work out.
Trigonometric ratios sin and cosec are positive in the 1st and 2nd quadrant and in the 3rd and 4th quadrant are negative. Cos and sec are positive in the 1st and 4th quadrant. Tan and cot are positive in the 3rd and 1st quadrant.
Complete step-by-step answer:
First write 144 = 180 - 36 and proceed we will get,
$
= \left( {\dfrac{{\sec 18^\circ }}{{\sec \left( {180^\circ - 36^\circ } \right)}} + \dfrac{{\cos ec18^\circ }}{{\cos ec\left( {180^\circ - 36^\circ } \right)}}} \right) \\
= \left( {\dfrac{{\sec 18^\circ }}{{ - sec36^\circ }} + \dfrac{{\cos ec18^\circ }}{{\cos ec36^\circ }}} \right) \\
$
Now converting the above expression in the form of sin and cos
We will get,
$
= \left( { - \dfrac{{\dfrac{1}{{\cos 18^\circ }}}}{{\dfrac{1}{{\cos 36^\circ }}}} + \dfrac{{\dfrac{1}{{\sin 18^\circ }}}}{{\dfrac{1}{{\sin 36^\circ }}}}} \right) \\
= \left( { - \dfrac{{\cos 36^\circ }}{{\cos 18^\circ }} + \dfrac{{\sin 36^\circ }}{{\sin 18^\circ }}} \right) \\
$
On taking LCM and solving we get,
$ = \left( {\dfrac{{ - \cos 36^\circ \sin 18^\circ + \sin 36^\circ \cos 18^\circ }}{{\cos 18^\circ \sin 18^\circ }}} \right)$
Use the sin (A-B) formula then simplify we get,
$
= \left( {\dfrac{{\sin \left( {36^\circ - 18^\circ } \right)}}{{\cos 18^\circ \sin 18^\circ }}} \right) \\
= \left( {\dfrac{{\sin 18^\circ }}{{\cos 18^\circ \sin 18^\circ }}} \right) \\
= \dfrac{1}{{\cos 18^\circ }} \\
= \sec 18^\circ \\
$
The above expression is equals to $\sec 18^\circ $
So, the correct answer is “Option A”.
Note: Scientific calculators have sin, cos, and tan functions, as well as the inverse functions. It's worth taking a few minutes to work out.
Trigonometric ratios sin and cosec are positive in the 1st and 2nd quadrant and in the 3rd and 4th quadrant are negative. Cos and sec are positive in the 1st and 4th quadrant. Tan and cot are positive in the 3rd and 1st quadrant.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

Which among the following are examples of coming together class 11 social science CBSE

