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What is the largest number you can make using each of the digits 7, 1, 0, 2 and 9 just once?

Answer
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Hint: For solving this question you should know about the increment and decrement order of the numbers. And by this order we can solve this type of question. In this first we will take all the numbers and we will set all the numbers in ascending order and descending order. And by settling them in descending order we can find the largest number and by ascending order we can find the smallest number.

Complete step by step answer:
According to the question we have to find the largest number using digits 7, 1, 0, 2, 9 and we can use one digit only once.
The largest number can be made by any numbers but that will always remain small for the greater number from that. So, we can only make some digits as a large number for those digits.
If we take an example: 87420
As we move to the left the value of the placeholder increases. Therefore, we can say that for finding any largest number we have to write the largest digits left side and small digits right side of that.
5 digits means the first place holder will be ten thousand.
80,000 is much bigger than 40,000.
So, arrange this in the descending order to get 87, 420.
Now, according to our question the digits are 7, 1, 0, 2, 9.
For getting the largest number set these as a descending order: 9, 7, 2, 1, 0
Now the largest number is 97, 210
So, the largest number of the digits 7, 1, 0, 2 and 9 is 97210.

Note: The largest number of digits is easy to find. And we can find it just by settling them in descending order. But if the question asks for the smallest number then we have to arrange it in the ascending order. And in that we will put small digits right left and the greater digit right side.