
How is the kinetic energy versus temperature graph for a given substance?
Answer
560.1k+ views
Hint: Write the relationship between the average kinetic energy of the molecules and absolute temperature. From this relationship, decide if the plot is a straight line or a curve. For a curve, decide the shape of the curve from the relationship. If a straight line is obtained, then decide if the slope is positive or negative.
Complete Step by step answer: The average kinetic energy of the molecules is \[{\text{K}}{\text{.E = }}\dfrac{3}{2}{\text{kT }}\]
Here, \[{\text{K}}{\text{.E}}\] represents the average kinetic energy of the molecules, \[{\text{k}}\] represents the Boltzmann constant whereas \[{\text{T}}\] represents the absolute temperature.
Thus, the average kinetic energy of the molecules is directly proportional to the absolute temperature.
\[{\text{K}}{\text{.E }} \propto {\text{T}}\]
At absolute zero, the average kinetic energy of the molecules has a value of zero. With increase in the absolute temperature, the average kinetic energy of the molecules also increases.
For one mole of the ideal gas, the average molecular kinetic energy of molecules is plotted on the Y axis whereas the absolute temperature is plotted on the X axis. The plot is a straight line passing through the origin and having a positive slope. Such a plot is obtained in the plot of the option (C).
Hence, the correct option is the option (C).
Note: We should note that the kinetic energy is expressed in terms of temperature and not the velocity. So we can also say that there would be relation in between the temperature and the velocity of molecules.The Boltzmann constant \[{\text{k = }}\dfrac{{\text{R}}}{{{{\text{N}}_{\text{A}}}}}\] .Here, \[{\text{R}}\] is the ideal gas constant and \[{{\text{N}}_{\text{A}}}\] is the Avogadro’s number. The value of the Boltzmann constant is \[{\text{1}}{\text{.38}} \times {\text{1}}{{\text{0}}^{ - {\text{23}}}}{\text{ Joule molecul}}{{\text{e}}^{ - 1}}{\text{ }}{{\text{K}}^{ - 1}}\] .
Complete Step by step answer: The average kinetic energy of the molecules is \[{\text{K}}{\text{.E = }}\dfrac{3}{2}{\text{kT }}\]
Here, \[{\text{K}}{\text{.E}}\] represents the average kinetic energy of the molecules, \[{\text{k}}\] represents the Boltzmann constant whereas \[{\text{T}}\] represents the absolute temperature.
Thus, the average kinetic energy of the molecules is directly proportional to the absolute temperature.
\[{\text{K}}{\text{.E }} \propto {\text{T}}\]
At absolute zero, the average kinetic energy of the molecules has a value of zero. With increase in the absolute temperature, the average kinetic energy of the molecules also increases.
For one mole of the ideal gas, the average molecular kinetic energy of molecules is plotted on the Y axis whereas the absolute temperature is plotted on the X axis. The plot is a straight line passing through the origin and having a positive slope. Such a plot is obtained in the plot of the option (C).
Hence, the correct option is the option (C).
Note: We should note that the kinetic energy is expressed in terms of temperature and not the velocity. So we can also say that there would be relation in between the temperature and the velocity of molecules.The Boltzmann constant \[{\text{k = }}\dfrac{{\text{R}}}{{{{\text{N}}_{\text{A}}}}}\] .Here, \[{\text{R}}\] is the ideal gas constant and \[{{\text{N}}_{\text{A}}}\] is the Avogadro’s number. The value of the Boltzmann constant is \[{\text{1}}{\text{.38}} \times {\text{1}}{{\text{0}}^{ - {\text{23}}}}{\text{ Joule molecul}}{{\text{e}}^{ - 1}}{\text{ }}{{\text{K}}^{ - 1}}\] .
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

