Question

# When kept in open air, the crystals of washing soda lose 9 molecules of water to form a monohydrate.$\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\text{.10}{{\text{H}}_{\text{2}}}\text{O}\xrightarrow[\text{to air}]{\text{exposed}}\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\text{.}{{\text{H}}_{\text{2}}}\text{O + 9}{{\text{H}}_{\text{2}}}\text{O}$This process is called:(A) efflorescence(B) deliquescence(C) dehydration(D) hydration

Hint: Recollect what term is used for the process of removal of water from any substance. This term is generally used when water of crystallization is being removed.

$\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\text{.10}{{\text{H}}_{\text{2}}}\text{O}\xrightarrow[\text{to air}]{\text{exposed}}\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\text{.}{{\text{H}}_{\text{2}}}\text{O + 9}{{\text{H}}_{\text{2}}}\text{O}$