Question

IUPAC name of $ {{\left[ Fe\left( {{O}_{2}} \right){{\left( CN \right)}_{4}}Cl \right]}^{4-}} $ is
(A) Chlor Tetracyano dioxoferrate $ \left( II \right) $ ion.
(B) Chlor Tetracyano peroxoferrate $ \left( II \right) $ ion.
(C) Chlor Tetracyano superoxoferrate $ \left( II \right) $ ion.
(D) Tetracyano Chloro superoxoferrate $ \left( II \right) $ ion.

Answer 1

Hint :We know that $ {{\left[ Fe\left( {{O}_{2}} \right){{\left( CN \right)}_{4}}Cl \right]}^{4-}} $ is a coordination compound and in this compound, the coordination complex is the positive part and the chloride ions are the negative part. The oxidation state of cobalt in this compound will be $ +4. $ If the coordination complex has an ambidentate ligand then the complex will show linkage isomerism.

Complete Step By Step Answer:
Some rules that must be followed while naming the coordination complex. Step by step method is given below:
In the IUPAC name, the positive ion must be named first and then the negative ion must be named. The compounds written in the complex part must be written in one word without any gap. There are some numerical prefixes used like for $ 2 $ it is di, for $ 3 $ it is tri, for $ 4 $ it is tetra, and these must be used without the hyphen.
The names of ligands must be written in the alphabetic order even if they are negative, positive, or neutral.
The name of the central metal ion must be written after the name of ligands. Compounds having complex as a cation, first write the ligand name, then the central metal ion with its oxidation state and then the name of the anion.
Complex having complex as an anion, first write the name of cation and then the name of ligand and to the central metal atom add –ate along with its oxidation state.
The IUPAC name of $ {{\left[ Fe\left( {{O}_{2}} \right){{\left( CN \right)}_{4}}Cl \right]}^{4-}} $ is Chlorotetracyano superoxoferrate $ ~\left( II \right) $ ion since chlorine and cyanide ligands are written as chloro and tetrracyano. The prefix tetra indicates four. The ligand $ {{O}_{2}} $ is named as superoxo. The iron metal is named ferrate $ ~\left( II \right) $ ion as it is a part of an anionic complex ion. The oxidation state of iron is written in roman numerals inside parenthesis.
Therefore, correct answer is option C. i.e. IUPAC name of $ {{\left[ Fe\left( {{O}_{2}} \right){{\left( CN \right)}_{4}}Cl \right]}^{4-}} $ is Chlorotetracyano superoxoferrate $ ~\left( II \right) $ ion.

Note :
Remember that in coordination complexes, the metal ion is attached to several ligands, so there are some ligands in which more than one atom in a unidentate ligand can act as a donor. These ligands are known as ambidentate ligands. So when an ambidentate ligand is attached with the central metal ion then it leads to linkage isomerism.