
It has been given that a motorboat is covering a particular distance in $6h$ moving downstream on a river. It will be covering the identical distance in $10h$ moving upstream. What will be the time it will be taking in order to cover the similar distance in still water?
$\begin{align}
& A.6.5h \\
& B.8h \\
& C.9h \\
& D.7.5h \\
\end{align}$
Answer
556.5k+ views
Hint: The distance covered will be equivalent to the product of the time taken in order to move downstream on a river and the sum of the velocity of the water and the velocity in the still water. The distance covered will be equivalent to the product of the time taken in order to move upstream on a river and the difference of the velocity in the still water and the velocity of the water. This will help you in answering this question.
Complete answer:
Let us assume that the velocity in the still water is $S$. The velocity of the water can be mentioned as $W$. The distance which has been covered in this situation can be written as $D$.
The distance covered will be equivalent to the product of the time taken in order to move downstream on a river and the sum of the velocity of the water and the velocity in the still water. This can be written as an equation given as,
$D=6\left( S+W \right)$
The distance covered will be equivalent to the product of the time taken in order to move upstream on a river and the difference of the velocity in the still water and the velocity of the water. This can be written as,
\[D=10\left( S-W \right)\]
As this distance covered has mentioned to be equivalent, we can write that,
\[6\left( S+W \right)=10\left( S-W \right)\]
Simplifying this equation can be shown as,
\[S=4W\]
Therefore the distance covered can be obtained as,
\[D=7.5hr\]
Therefore the correct answer for the question has been found.
This has been mentioned as option D.
Note:
The velocity of a body can be defined as the variation of the displacement of the body with respect to the time taken. The displacement of the body can be found by taking the perpendicular distance between the initial and final position of the body. Both these quantities are found to be vectors.
Complete answer:
Let us assume that the velocity in the still water is $S$. The velocity of the water can be mentioned as $W$. The distance which has been covered in this situation can be written as $D$.
The distance covered will be equivalent to the product of the time taken in order to move downstream on a river and the sum of the velocity of the water and the velocity in the still water. This can be written as an equation given as,
$D=6\left( S+W \right)$
The distance covered will be equivalent to the product of the time taken in order to move upstream on a river and the difference of the velocity in the still water and the velocity of the water. This can be written as,
\[D=10\left( S-W \right)\]
As this distance covered has mentioned to be equivalent, we can write that,
\[6\left( S+W \right)=10\left( S-W \right)\]
Simplifying this equation can be shown as,
\[S=4W\]
Therefore the distance covered can be obtained as,
\[D=7.5hr\]
Therefore the correct answer for the question has been found.
This has been mentioned as option D.
Note:
The velocity of a body can be defined as the variation of the displacement of the body with respect to the time taken. The displacement of the body can be found by taking the perpendicular distance between the initial and final position of the body. Both these quantities are found to be vectors.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

