Courses for Kids
Free study material
Offline Centres
Store Icon

 Is zero a rational number? Can you write it in the form of $\dfrac{p}{q}$, where p and q are integers and $q \ne 0$?

Last updated date: 17th Jul 2024
Total views: 353.8k
Views today: 10.53k
353.8k+ views

Hint: Try writing various fractions such that 0 is in the numerator and it is divided by some integer q such that $q \ne 0$. If all such numbers exist then zero is a rational number.

Complete answer:

As we know a rational number is a number which is represented in the form of $\dfrac{a}{b}$ , where $b \ne 0$ and a and b have not any common factors except 1.

Then it can be represented as a fraction of two integers.

For example $\dfrac{{10}}{{15}}$ 

As we see this a fraction but not written in lowest form of fraction so first convert this fraction into lowest form of fraction.

$ \Rightarrow \dfrac{{10}}{{15}} = \dfrac{{2 \times 5}}{{3 \times 5}}$

Now cancel out the common terms we have,

$ \Rightarrow \dfrac{{10}}{{15}} = \dfrac{2}{3}$

So this fraction converts into a rational number where ($3 \ne 0$) and has no common factors except 1.

Now consider the given number zero (0).

As we know 0 is an integer.

So when we divide 0 by any integer except itself the value is 0.

So 0 is written as $\dfrac{0}{q} = \dfrac{p}{q}$ where p and q both are integers and (P = 0, $q \ne 0$) and it is written in lowest form of fraction (i.e. it has no common factors except 1).

Therefore 0 is a rational number.

Note: In the definition of rational numbers such that $\dfrac{p}{q},q \ne 0$. It is defined that q should not be equal to zero because if it is not so, we can have a fraction of the form finite divided by 0, which will be nothing but not-denied. Hence this condition is imposed to take into consideration only defined fractions.