
Is $AgCl$ soluble in water ?
Answer
491.1k+ views
Hint: The solubility of an ionic compound depends on its lattice energy and hydration energy. For solubility, compare both energies for a given compound. The compound is soluble in water if and only if its lattice energy is lesser than its hydration energy.
Complete answer:
The solubility of Silver Chloride can be in two different ways. Firstly it is according to the Fajan Rule which tells us about the polarizing power of any ion . According to this polarizing power of ions depends on charge by radius ratio . For $AgCl$ , $A{g^ + }$ has more polarizing power and thus as a result covalent character is developed in the compound. We can also say $AgCl$ has become non polar in nature. Since water is polar so it will dissolve only polar compounds .Hence $AgCl$ is insoluble in water.
Secondly , the solubility of a compound can be explained on the basis of its lattice energy and hydration energy. In the case of $AgCl$ the attraction between the $AgCl$ molecule itself is greater than attraction between $AgCl$ and water . Thus the hydration enthalpy of the ${\text{ aq}}{\text{. }}AgCl$ is not sufficient to overcome the lattice enthalpy of its ions.
Thus we can say that $AgCl$ is insoluble in water.
Note:
$NaCl$ is soluble in water whereas $AgCl$ don’t .This is explained by Fajan Rule . Also $KCl$ is soluble in water too. The solubility product also helps in knowing the solubility of the given compound. The solubility product of $AgCl$ in water is $1.7{\text{ }} \times {\text{ 1}}{{\text{0}}^{ - 10}}{\text{ mo}}{{\text{l}}^2}{\text{ d}}{{\text{m}}^{ - 6}}$ .
Complete answer:
The solubility of Silver Chloride can be in two different ways. Firstly it is according to the Fajan Rule which tells us about the polarizing power of any ion . According to this polarizing power of ions depends on charge by radius ratio . For $AgCl$ , $A{g^ + }$ has more polarizing power and thus as a result covalent character is developed in the compound. We can also say $AgCl$ has become non polar in nature. Since water is polar so it will dissolve only polar compounds .Hence $AgCl$ is insoluble in water.
Secondly , the solubility of a compound can be explained on the basis of its lattice energy and hydration energy. In the case of $AgCl$ the attraction between the $AgCl$ molecule itself is greater than attraction between $AgCl$ and water . Thus the hydration enthalpy of the ${\text{ aq}}{\text{. }}AgCl$ is not sufficient to overcome the lattice enthalpy of its ions.
Thus we can say that $AgCl$ is insoluble in water.
Note:
$NaCl$ is soluble in water whereas $AgCl$ don’t .This is explained by Fajan Rule . Also $KCl$ is soluble in water too. The solubility product also helps in knowing the solubility of the given compound. The solubility product of $AgCl$ in water is $1.7{\text{ }} \times {\text{ 1}}{{\text{0}}^{ - 10}}{\text{ mo}}{{\text{l}}^2}{\text{ d}}{{\text{m}}^{ - 6}}$ .
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

