Question

Inversion of cane sugar is a pseudo first-order reaction. Give reason.

Answer 1

Hint: The number of chemical reactions going to involve in the chemical reaction is going to decide the order of the chemical reaction. If there are two reactants in a chemical reaction but only one reactant is going to play a role in the order of the chemical reaction then the chemical reaction is called pseudo first-order chemical reaction.

Complete answer:
- In the question it is asked to give reason behind the pseudo first-order reaction of inversion of cane sugar.
- First we have to write a chemical reaction for inversion of cane sugar and it is as follows.
\[\underset{Cane\text{ }sugar}{\mathop{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}\,+{{H}_{2}}O\xrightarrow{{{H}^{+}}}{{C}_{6}}{{H}_{12}}{{O}_{6}}+{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
- In the above chemical reaction we can see that one mole of cane sugar is going to react with one mole of moles and forms two products.
- As per the above chemical reaction the chemical reaction is an example for second order reaction because of the involvement of the two chemical reactants in the reaction.
- But it is found that the order of the above chemical reaction is first order.
- The reason behind it is that the water which is involved in the above chemical reaction is solvent means present in excess amount then the water is not going to consider a reactant.
- Therefore the inversion of the cane sugar is an example for pseudo first-order reaction.

Note:
The rate of the chemical reaction in the inversion of cane sugar is directly proportional to the concentration of the cane sugar only not on the concentration of the water.
\[r\alpha [{{C}_{12}}{{H}_{22}}{{O}_{11}}]\]