
In which of the following pairs, the two species are iso-structural?
A. \[BrO_3^ - \] and \[Xe{O_3}\]
B. \[S{F_4}\] and \[Xe{F_4}\]
C. \[SO_3^{2 - }\] and \[NO_3^ - \]
D. \[B{F_3}\] and \[N{F_3}\]
Answer
555k+ views
Hint: Iso-structural is defined as those species which contain the same number of atoms arranged in the same structural form which same number of chemical bonds and lone pairs of electrons..
Complete step by step answer:
A. \[BrO_3^ - \] and \[Xe{O_3}\]
In this compound, the total number of atoms present in this structure is 4, lone pair present is 7, minus charge shows that it contains extra electrons.
In this compound, the total number of atoms present in this structure is 4, lone pair present is 7.
Both the given structures are isostructural to each other.
B. \[S{F_4}\] and \[Xe{F_4}\]
In this compound, the total number of atoms present in this structure is 4, lone pair present is 1.
In this compound, the total number of atoms present in this structure is 4, lone pair present is 2.
Both the given compounds are not isostructural to each other.
C. \[SO_3^{2 - }\] and \[NO_3^ - \]
In this compound, the total number of atoms present in this structure is 4, lone pair present is 8. Two single bonds and one double bond is present. The total charge is -2.
In this compound, the total number of atoms present in this structure is 4, lone pair present is 8. Two single bonds and one double bond is present. The total charge is -1.
Both the given compounds are not isostructural to each other.
D. D. \[B{F_3}\] and \[N{F_3}\]
In this compound, the total number of atoms present is 4, the total number of lone pairs present is 9 and three single bonds are present.
In this compound, the total number of atoms present is 4, the total number of lone pairs present is 10 and three single bonds are present.
Both the given compounds are not isostructural to each other.
So, the correct answer is Option A.
Note: The correct option can also be found by the formula of hybridization which is shown below.
\[ \Rightarrow \dfrac{1}{2}\left[ {no\;of\;valence\;{e^ - }on\;central\;atom + no\;of\;monovalent\;atom \pm ch\arg e} \right]\]
For \[BrO_3^ - \]
\[ \Rightarrow \dfrac{1}{2}\left[ {7 + 0 + 1} \right] = 4\;s{p^3}\]
For \[Xe{O_3}\]
\[ \Rightarrow \dfrac{1}{2}\left[ {8 + 0 \pm 0} \right] = 4\;s{p^3}\]
Complete step by step answer:
A. \[BrO_3^ - \] and \[Xe{O_3}\]
In this compound, the total number of atoms present in this structure is 4, lone pair present is 7, minus charge shows that it contains extra electrons.
In this compound, the total number of atoms present in this structure is 4, lone pair present is 7.
Both the given structures are isostructural to each other.
B. \[S{F_4}\] and \[Xe{F_4}\]
In this compound, the total number of atoms present in this structure is 4, lone pair present is 1.
In this compound, the total number of atoms present in this structure is 4, lone pair present is 2.
Both the given compounds are not isostructural to each other.
C. \[SO_3^{2 - }\] and \[NO_3^ - \]
In this compound, the total number of atoms present in this structure is 4, lone pair present is 8. Two single bonds and one double bond is present. The total charge is -2.
In this compound, the total number of atoms present in this structure is 4, lone pair present is 8. Two single bonds and one double bond is present. The total charge is -1.
Both the given compounds are not isostructural to each other.
D. D. \[B{F_3}\] and \[N{F_3}\]
In this compound, the total number of atoms present is 4, the total number of lone pairs present is 9 and three single bonds are present.
In this compound, the total number of atoms present is 4, the total number of lone pairs present is 10 and three single bonds are present.
Both the given compounds are not isostructural to each other.
So, the correct answer is Option A.
Note: The correct option can also be found by the formula of hybridization which is shown below.
\[ \Rightarrow \dfrac{1}{2}\left[ {no\;of\;valence\;{e^ - }on\;central\;atom + no\;of\;monovalent\;atom \pm ch\arg e} \right]\]
For \[BrO_3^ - \]
\[ \Rightarrow \dfrac{1}{2}\left[ {7 + 0 + 1} \right] = 4\;s{p^3}\]
For \[Xe{O_3}\]
\[ \Rightarrow \dfrac{1}{2}\left[ {8 + 0 \pm 0} \right] = 4\;s{p^3}\]
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

