
In the given figure the boundary of the shaded region consists of a semicircular and inside two semicircles and one outside of the same diameters. The diameter of the largest semicircle is 14 cm and those of smallest ones are 3.5 cm. Calculate the shaded area.
Answer
603.9k+ views
Hint: In this area based question we have to find the area of the shaded region. It is clear that the shaded region can easily be obtained by reducing the two smaller inside semicircles from the larger semicircle and adding this to the area of the outer smaller semicircle. Use this concept along with a basic area formula for the area of semicircles to get the answer.
Complete step-by-step answer:
As we know that the area (A) of the circle is $\pi {r^2}$ (where r is the radius of the circle).
Now as we know that diameter (d) of a circle is twice the radius.
$
\Rightarrow d = 2r \\
\Rightarrow r = \dfrac{d}{2} \\
$
So substitute this value in the formula of area of circle we have
$ \Rightarrow A = \pi {\left( {\dfrac{d}{2}} \right)^2} = \pi \dfrac{{{d^2}}}{4}$
Now the area of the semi-circle (${A_1}$) is half the area of the circle.
$ \Rightarrow {A_1} = \dfrac{A}{2} = \dfrac{{\pi \dfrac{{{d^2}}}{4}}}{2} = \pi \dfrac{{{d^2}}}{8}$ Sq. unit.
Now it is given that the diameter (${D_1}$) of big shaded semicircle is 14 cm and the diameter (${D_2}$) of smaller unshaded semicircles 3.5 cm as given (see figure) so the diameter (${D_3}$) of the smaller shaded semicircle is:
Diameter of big shaded semicircle – twice multiplied by diameter of smaller unshaded semicircle.
$ \Rightarrow {D_3} = \left( {{D_1} - 2 \times {D_2}} \right) = 14 - 2 \times 3.5 = 14 - 7 = 7{\text{ cm}}$.
Now in the figure the area (${A_2}$) of the shaded region is = Area of big semi-circle having diameter 14 cm + Area of smaller semi-circle having diameter 7 cm – twice multiplied by area of semi-circle having diameter 3.5 cm.
$ \Rightarrow {A_2} = \pi \dfrac{{{{14}^2}}}{8} + \pi \dfrac{{{7^2}}}{8} - 2\pi \dfrac{{{{\left( {3.5} \right)}^2}}}{8}$
$ \Rightarrow {A_2} = \dfrac{\pi }{8}\left[ {{{14}^2} + {7^2} - 2{{\left( {3.5} \right)}^2}} \right] = \dfrac{\pi }{8}\left( {220.5} \right) = 27.5625\left( \pi \right) = \dfrac{{22}}{7}\left( {27.5625} \right) = 86.54625$ Sq. cm.
Note: Whenever we face such types of problems the key concept is to have the good understanding of the diagrammatic representation of the figure in order to figure out the required shaded region. The good gist of the basic area formula for curves like circle always helps to get on the right track to reach the answer.
Complete step-by-step answer:
As we know that the area (A) of the circle is $\pi {r^2}$ (where r is the radius of the circle).
Now as we know that diameter (d) of a circle is twice the radius.
$
\Rightarrow d = 2r \\
\Rightarrow r = \dfrac{d}{2} \\
$
So substitute this value in the formula of area of circle we have
$ \Rightarrow A = \pi {\left( {\dfrac{d}{2}} \right)^2} = \pi \dfrac{{{d^2}}}{4}$
Now the area of the semi-circle (${A_1}$) is half the area of the circle.
$ \Rightarrow {A_1} = \dfrac{A}{2} = \dfrac{{\pi \dfrac{{{d^2}}}{4}}}{2} = \pi \dfrac{{{d^2}}}{8}$ Sq. unit.
Now it is given that the diameter (${D_1}$) of big shaded semicircle is 14 cm and the diameter (${D_2}$) of smaller unshaded semicircles 3.5 cm as given (see figure) so the diameter (${D_3}$) of the smaller shaded semicircle is:
Diameter of big shaded semicircle – twice multiplied by diameter of smaller unshaded semicircle.
$ \Rightarrow {D_3} = \left( {{D_1} - 2 \times {D_2}} \right) = 14 - 2 \times 3.5 = 14 - 7 = 7{\text{ cm}}$.
Now in the figure the area (${A_2}$) of the shaded region is = Area of big semi-circle having diameter 14 cm + Area of smaller semi-circle having diameter 7 cm – twice multiplied by area of semi-circle having diameter 3.5 cm.
$ \Rightarrow {A_2} = \pi \dfrac{{{{14}^2}}}{8} + \pi \dfrac{{{7^2}}}{8} - 2\pi \dfrac{{{{\left( {3.5} \right)}^2}}}{8}$
$ \Rightarrow {A_2} = \dfrac{\pi }{8}\left[ {{{14}^2} + {7^2} - 2{{\left( {3.5} \right)}^2}} \right] = \dfrac{\pi }{8}\left( {220.5} \right) = 27.5625\left( \pi \right) = \dfrac{{22}}{7}\left( {27.5625} \right) = 86.54625$ Sq. cm.
Note: Whenever we face such types of problems the key concept is to have the good understanding of the diagrammatic representation of the figure in order to figure out the required shaded region. The good gist of the basic area formula for curves like circle always helps to get on the right track to reach the answer.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

