Question

In the given figure, find the magnitude and nature of zero error.

Answer 1

Hint:If the zero of vernier scale is in right of the zero of main scale then the nature of zero error will be positive and if the zero of vernier scale is in the left of the zero of the main scale then the nature of the zero error will be negative.
Magnitude of zero error $ = $value of vernier scale where it matches with main scale $ \times $Least Count (or$Z = N + x \times VC$).

Complete Step by Step Answer: In the given question, zero of vernier scale is the right of zero of the main scale. Hence it has positive zero error.
Now the number of Vernier Scale Division (VSD) in vernier scale is $ = 10$
Also the Main Scale Division (MSD) has length of $1mm$in main scale division, so the least count $\left( {LC = x} \right)$ is given by,
$x = LC = \dfrac{{1\,\,MSD}}{{10}} = \dfrac{{1mm}}{{10}}$
$x = LC = 0.1mm$
Hence the magnitude of zero error
$Z = N + x \times VC$
Here $N = 0,\,\,x = LC = 0.1mm$and $VC = 5$ (where the vernier scale matches with main scale)
$Z = 0 + LC \times VC$
\[Z = 0 + x \times VC\]
$Z = 0 + 0.1 \times 5$
$Z = 0.5mm$
Hence, nature of zero error $ = $positive
Magnitude of zero error, $Z = 0.5mm$

Note:On the given question where the value of vernier scale matches with main scale is shown below the figure.