Answer
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Hint: The diode is connected in forward bias. Here the two resistances are connected in series. Hence the total resistance of the circuit is the sum of those two resistances. Then by applying Ohm’s law and rearranging the equation and then substituting the values of voltage and total resistance of series connection we will get the current through the battery.
Formula used:
According to Ohm’s law the voltage or potential difference and the current flowing through a conductor are directly proportional. And here the proportionality constant is the resistance.
$V=IR$
where, V is the voltage or potential difference.
I is the current flowing through a conductor.
and R is the resistance.
Complete answer:
Here the two resistances are connected in series. Hence the total resistance of the circuit is the sum of those two resistances.
Given that ${{R}_{1}}=5\Omega \And {{R}_{2}}=5\Omega $ .
Thus ${{R}_{net}}={{R}_{1}}+{{R}_{2}}$
$\Rightarrow {{R}_{net}}=5+5$
$\therefore {{R}_{net}}=10\Omega $
According to Ohm’s law the voltage or potential difference and the current flowing through a conductor are directly proportional. And here the proportionality constant is the resistance.
$V=IR$ ………..(1)
where, V is the voltage or potential difference.
I is the current flowing through a conductor.
and R is the resistance.
Also given that V=10V
By calculation the net resistance, ${{R}_{net}}=10\Omega $
Then by rearranging the equation (1) and then substituting the values of voltage and total resistance of series connection we will get the current through the battery we get,
$I=\dfrac{V}{R}$
$\Rightarrow I=\dfrac{10V}{10\Omega }$
$\therefore I=1A$
Therefore option (C ) is correct.
Note:
According to Ohm’s law the voltage or potential difference and the current flowing through a conductor are directly proportional . And here the proportionality constant is the resistance. In a circuit if there is more than one resistor used, then first check whether they are connected in series or parallel. Then apply the equation according to it to find the total resistance of the combination.
Formula used:
According to Ohm’s law the voltage or potential difference and the current flowing through a conductor are directly proportional. And here the proportionality constant is the resistance.
$V=IR$
where, V is the voltage or potential difference.
I is the current flowing through a conductor.
and R is the resistance.
Complete answer:
Here the two resistances are connected in series. Hence the total resistance of the circuit is the sum of those two resistances.
Given that ${{R}_{1}}=5\Omega \And {{R}_{2}}=5\Omega $ .
Thus ${{R}_{net}}={{R}_{1}}+{{R}_{2}}$
$\Rightarrow {{R}_{net}}=5+5$
$\therefore {{R}_{net}}=10\Omega $
According to Ohm’s law the voltage or potential difference and the current flowing through a conductor are directly proportional. And here the proportionality constant is the resistance.
$V=IR$ ………..(1)
where, V is the voltage or potential difference.
I is the current flowing through a conductor.
and R is the resistance.
Also given that V=10V
By calculation the net resistance, ${{R}_{net}}=10\Omega $
Then by rearranging the equation (1) and then substituting the values of voltage and total resistance of series connection we will get the current through the battery we get,
$I=\dfrac{V}{R}$
$\Rightarrow I=\dfrac{10V}{10\Omega }$
$\therefore I=1A$
Therefore option (C ) is correct.
Note:
According to Ohm’s law the voltage or potential difference and the current flowing through a conductor are directly proportional . And here the proportionality constant is the resistance. In a circuit if there is more than one resistor used, then first check whether they are connected in series or parallel. Then apply the equation according to it to find the total resistance of the combination.
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