
In the following reaction, the product S is:
(A)
(B)
(C)
(D)





Answer
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Hint: To solve this question we should know about ozonolysis, reductive workup. A carbonyl group undergoes nucleophilic addition reaction that is whenever nucleophile attacks on carbonyl carbon.
Complete answer:
Let's go step by step reaction for better understanding of the reaction:
Let the
be' H'.
(I) Ozone molecule is added to molecule H that is molecule H undergoes ozonolysis forming corresponding ozonide. The ozonide formed undergoes reductive workup. In the reductive workup process the ozonide is treated with mild reagents like Zn dust in water or dimethyl sulfide resulting in formation of carbonyl compounds. 5-methyl-2-(2oxoethyl)benzaldehyde is formed after the ozonolysis followed by reductive workup.
(II) Addition of ammonia to 5-methyl-2-(2oxoethyl)benzaldehyde. The ammonia molecule can be represented as . The attack the carbonyl group. When attacks the positively charged carbonyl carbon to form a new bond. As the new bond is formed, between the carbon and oxygen is broken. The electron pair goes to oxygen, which acquires a negative charge. The (electrophile) attacks negatively charged oxygen to form the addition product (III)
(III) attacks other carbonyl carbon due to which a new bond is formed, between the carbon and oxygen is broken. The electron pair goes to oxygen, which acquires a negative charge. ion lost by , attacks the negatively charged oxygen. Thus (IV) is formed as the addition product.
(V) Two molecules of water are removed as a result 7-methylisoquinoline is formed.
Thus, option A is the correct answer.
Note:
The nucleophile attacks the positively charged carbonyl carbon to form a new bond. As the new bond is formed, between the carbon and oxygen is broken. The electron pair goes to oxygen, which acquires a negative charge. The electrophile attacks negatively charged oxygen to form the additional product. This type of reaction is known as nucleophilic addition reaction.
Complete answer:
Let's go step by step reaction for better understanding of the reaction:
Let the

(I) Ozone molecule is added to molecule H that is molecule H undergoes ozonolysis forming corresponding ozonide. The ozonide formed undergoes reductive workup. In the reductive workup process the ozonide is treated with mild reagents like Zn dust in water or dimethyl sulfide resulting in formation of carbonyl compounds. 5-methyl-2-(2oxoethyl)benzaldehyde is formed after the ozonolysis followed by reductive workup.
(II) Addition of ammonia to 5-methyl-2-(2oxoethyl)benzaldehyde. The ammonia molecule can be represented as
(III)
(V) Two molecules of water are removed as a result 7-methylisoquinoline is formed.

Thus, option A is the correct answer.
Note:
The nucleophile attacks the positively charged carbonyl carbon to form a new bond. As the new bond is formed,
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