Question

In sodium dihydrogen pyrophosphate, the number of non-acidic hydrogen is ‘x’, the number of oxygen atoms is 'y', and the oxidation state of each phosphorus atom is 'z', then the value of (x+y-z) is:
(a)- 4
(b)- 6
(c)- 0
(d)- 2

Answer 1

Hint: Sodium hydrogen pyro phosphite is an inorganic compound in which the elements present are oxygen, hydrogen, sodium, and phosphorus, so its formula is $N{a}_2{H}_2{P}_2{O}_7$. If the hydrogen atom is not attached to an electronegative atom then it is a non-acidic hydrogen atom.

Complete answer:
Disodium dihydrogen diphosphate is an IUPAC name of Sodium dihydrogen pyrophosphate which is an inorganic compound in which the elements present are oxygen, hydrogen, sodium, and phosphorus. The formula of Sodium hydrogen pyro phosphite is $N{a}_2{H}_2{P}_2{O}_7$.
Let us see the structure of the compound.

If the hydrogen atom is not attached to an electronegative atom then it is a non-acidic hydrogen atom. As we can see that there are two hydrogen atoms in the compound and both the hydrogen atoms are attached to the oxygen atom, an oxygen atom is electronegative, so both the hydrogen atoms are acidic hydrogen.
Therefore, the number of non-acidic hydrogen ‘x’ is 0.
From the formula we can see that the number of oxygen atoms are 7, therefore, ‘y ‘ is 7.
Now, we have to find the oxidation number of phosphorus in the compound. The oxidation state is calculated as follows:
$N{a}_2{H}_2{P}_2{O}_7$
$2\text{ x (+1) + 2 x}\text{ (+1) + 2}x\text{ + 7 x (-2) = 0}$
$\text{2 + 2 + 2}x\text{ - 14 = 0}$
$x=+5$
Therefore, the value of ‘z’ is +5.
Now, we have to find the value of (x+y-z), so by putting the values, we get:
$(x+y-z)=(0+7-(+5))$
$(x+y-z)=7-5=2$
So, the answer is 2.

Therefore, the correct answer is an option (d).

Note:
In the compound, if the hydrogen atom was directly attached to the phosphorus atom then, it would be counted as a non-acidic hydrogen atom. While calculating the oxidation state, the oxidation number of sodium is taken +1 because it is an alkali metal