Question

In extraction of metal by bessemerisation \[C{{u}_{2}}S\] is converted into:
A. \[C{{u}_{2}}O\]
B. \[CuO\]
C. \[Cu\]
D. \[CuFe{{O}_{2}}\]

Answer 1

Hint: \[C{{u}_{2}}S\] goes about as an oxidizing operator in the Bessemerisation process. Bessemerisation is the procedure which is utilized in the metallurgy of copper.
The correct answer is A.

Complete step-by-step answer:
In this technique a liquid issue (a blend of cuprous sulfide and ferrous sulfide) is diminished and gotten in the wake of refining of copper pyrites metal in a Bessemer converter.
Bessemerisation helps us to get extracted copper metal from liquid matte. The matte has been accumulated in a Bessemer converter. By the liquid matte air blown in Impact of air changes over \[C{{u}_{2}}S\] mostly \[C{{u}_{2}}O\] into which responds with remaining \[C{{u}_{2}}S\] to give liquid copper.

\[2C{{u}_{2}}S+3{{O}_{2}}\to 2C{{u}_{2}}O+2S{{O}_{2}}\]
\[2C{{u}_{2}}O+C{{u}_{2}}S\to 6Cu+S{{O}_{2}}\]
The copper so got is classified “Rankle copper” on the grounds that, as it hardens, \[S{{O}_{2}}\]covered up in it escapes out creating a rankle on its surface. Copper(I) Oxide is likewise called cuprous oxide an inorganic compound with the concoction equation \[C{{u}_{2}}O\].
So, on the bessemerisation reaction of copper we get the \[C{{u}_{2}}O\] as the product.
It is covalent in nature. Copper(I) oxide takes shape in a cubic structure. It is effectively diminished by hydrogen when warmed It experiences disproportionation in corrosive arrangements delivering copper (II) particles and copper.

Note: At the point when the cupric oxide is delicately warmed with metallic copper, it is changed over into cuprous oxide. It goes about as a decent erosion obstruction, because of responses at the surface between the copper and the oxygen in air to give a flimsy defensive oxide layer.