In a cyclic process, work done by the system is
A. Zero
B. More than the heat given to the system
C. Equal to the heat given to the system
D. Independent of the heat given to the system
Answer
655.2k+ views
Hint:
The thermodynamic system is the system that includes the change of the heat energy and the work from the system to the surrounding. Or from surrounding to the system.
Complete step by step answer:
The cyclic process is the process which has the same initial and the final state of the system. So, the energy of the system in its initial and final position is the same. So, the internal energy of the system is zero.
Consider the cyclic process in which the initial and the final state of the system is the same. Applying the first law of thermodynamic to the system:
$\Delta U$ = Q+W … (I)
Where, \Delta U is the internal energy of the system, Q is the heat applied to the system and W is the work done by the system.
For cyclic process you have,
$\Delta U$ = 0 … (II)
Substituting equation (II) in equation (I) you will get,
W = Q
So, the work done by the system is equal to the heat supplied to the system.
Option C is correct.
Note:
For normal processes, the work done is the product of the force and displacement.
So,
W=Fs
Where, F is the force and s is the displacement.
So, for cyclic process, s = 0
Thus, work done is zero.
But this is not true for the thermodynamic process.
The thermodynamic system is the system that includes the change of the heat energy and the work from the system to the surrounding. Or from surrounding to the system.
Complete step by step answer:
The cyclic process is the process which has the same initial and the final state of the system. So, the energy of the system in its initial and final position is the same. So, the internal energy of the system is zero.
Consider the cyclic process in which the initial and the final state of the system is the same. Applying the first law of thermodynamic to the system:
$\Delta U$ = Q+W … (I)
Where, \Delta U is the internal energy of the system, Q is the heat applied to the system and W is the work done by the system.
For cyclic process you have,
$\Delta U$ = 0 … (II)
Substituting equation (II) in equation (I) you will get,
W = Q
So, the work done by the system is equal to the heat supplied to the system.
Option C is correct.
Note:
For normal processes, the work done is the product of the force and displacement.
So,
W=Fs
Where, F is the force and s is the displacement.
So, for cyclic process, s = 0
Thus, work done is zero.
But this is not true for the thermodynamic process.
Recently Updated Pages
Lysosomes are known as suicidal bags of cell why class 11 biology CBSE

Father s age is three times the sum of the ages of-class-11-maths-CBSE

Give a comparative account of the classes of kingdom class 11 biology CBSE

The ceiling of a long hall is 25m high What is the class 11 physics CBSE

Name the Largest and the Smallest Cell in the Human Body ?

Draw a welllabelled diagram of a plant cell class 11 biology CBSE

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

