Question

i)Give the hydration of 1-butyne.
ii)Convert propyne to propyn-2-ol.

Answer 1

Hint:When butyne is reacted with water as we need to carry out the hydration reaction in the presence of sulphuric acid and mercury sulphate which results in butan-2-one.

Complete step-by-step answer:i) As the name suggests in the first one suggests hydration is considered as something containing the water particle.so we can further elaborate it as the the chemical process in which a addition reaction takes place where a hydroxyl group and a proton is added to the compound. Here we will further discuss the reaction of hydration of 1-butyne. So it will discuss it in brief as :
$$C{H}_{3}C{H}_{2}C\equiv CH+H_{2}O\underset{H_{2}S{O}_4}{\overset{HgS{O}_4}{\to }}C{H}_3-C{H}_2-C(OH)=C{H}_2\leftrightarrow C{H}_{3}C{H}_{2}C=OC{H}_3$$
We can say that when butyne is reacted with water as we need to carry out the hydration reaction in the presence of sulphuric acid and mercury sulphate which results in two products amongst which the one product is unstable while the other one is the stable one. Amongst the two products one is butan-2-one and this the stable product while the alcohol so obtained is unstable in nature.

ii) Here we need to convert propyne to propyn-2-ol
$$C{H}_{3}C\equiv CH\underset{H_{2}S{O}_4}{\overset{HgS{O}_4}{\to }}C{H}_{3}C(OH)C{H}_2\leftrightarrow C{H}_{3}C=OC{H}_3$$
Here also the same reagents are used and this will convert it easily. We reacted to propyne in the presence of mercury sulphate and sulphuric acid and we obtained prop-2-ol.

Note: In the tautomerism we come to know that the tautomers are the structural isomers of chemical compounds that readily get introverted.