
If $z = 2 + i\sqrt { - 3} $, tell the real and imaginary part from standard form.
Answer
587.1k+ views
Hint:
We can simplify the negative inside the radical using i. Then we can write the standard form of a complex number. Then we can compare them and find the real and imaginary part. The term without i will be the real part and term with i will give the imaginary part.
Complete step by step solution:
We are given the complex number,
$z = 2 + i\sqrt { - 3} $
We know that value inside the square root cannot be negative. So, we can expand the radicle as follows,
$ \Rightarrow z = 2 + i \times \sqrt 3 \times \sqrt { - 1} $
We know that the imaginary term i is the square root of negative one. So, we can write it as $i = \sqrt { - 1} $ . On substituting this in z, we get,
$ \Rightarrow z = 2 + i \times \sqrt 3 \times i$
Hence, we have,
$ \Rightarrow z = 2 + {i^2} \times \sqrt 3 $
We know that $i = \sqrt { - 1} $ . On taking the square, we get, \[{i^2} = - 1\] . Then z will become,
$ \Rightarrow z = 2 + \left( { - 1} \right)\sqrt 3 $
Hence, we have,
$ \Rightarrow z = 2 - \sqrt 3 $
We know that the standard form of a complex number is given by $z = x + iy$ where x is the real part and y is the imaginary part.
So, we can write z as,
$ \Rightarrow z = \left( {2 - \sqrt 3 } \right) + 0i = x + iy$
The real part is x. It is given by,
$ \Rightarrow x = \left( {2 - \sqrt 3 } \right)$
The imaginary part is y. From the equation we get,
$ \Rightarrow y = 0$
The given complex number in its standard form is given by $z = \left( {2 - \sqrt 3 } \right) + 0i$ where $\left( {2 - \sqrt 3 } \right)$ is the real part and 0 is the imaginary part.
Note:
We know that a complex number is defined as the ordered pair $\left( {x,y} \right)$ such that $z = x + iy$ where x and y are real numbers and i is the imaginary term which is given by $i = \sqrt { - 1} $ . We cannot take the given form of the complex number as a standard form as $\sqrt { - 3} $ is not a real number. After converting into standard form, we must note that the term with i is only considered as the imaginary part. As there is no term with i, the imaginary part will be zero.
We can simplify the negative inside the radical using i. Then we can write the standard form of a complex number. Then we can compare them and find the real and imaginary part. The term without i will be the real part and term with i will give the imaginary part.
Complete step by step solution:
We are given the complex number,
$z = 2 + i\sqrt { - 3} $
We know that value inside the square root cannot be negative. So, we can expand the radicle as follows,
$ \Rightarrow z = 2 + i \times \sqrt 3 \times \sqrt { - 1} $
We know that the imaginary term i is the square root of negative one. So, we can write it as $i = \sqrt { - 1} $ . On substituting this in z, we get,
$ \Rightarrow z = 2 + i \times \sqrt 3 \times i$
Hence, we have,
$ \Rightarrow z = 2 + {i^2} \times \sqrt 3 $
We know that $i = \sqrt { - 1} $ . On taking the square, we get, \[{i^2} = - 1\] . Then z will become,
$ \Rightarrow z = 2 + \left( { - 1} \right)\sqrt 3 $
Hence, we have,
$ \Rightarrow z = 2 - \sqrt 3 $
We know that the standard form of a complex number is given by $z = x + iy$ where x is the real part and y is the imaginary part.
So, we can write z as,
$ \Rightarrow z = \left( {2 - \sqrt 3 } \right) + 0i = x + iy$
The real part is x. It is given by,
$ \Rightarrow x = \left( {2 - \sqrt 3 } \right)$
The imaginary part is y. From the equation we get,
$ \Rightarrow y = 0$
The given complex number in its standard form is given by $z = \left( {2 - \sqrt 3 } \right) + 0i$ where $\left( {2 - \sqrt 3 } \right)$ is the real part and 0 is the imaginary part.
Note:
We know that a complex number is defined as the ordered pair $\left( {x,y} \right)$ such that $z = x + iy$ where x and y are real numbers and i is the imaginary term which is given by $i = \sqrt { - 1} $ . We cannot take the given form of the complex number as a standard form as $\sqrt { - 3} $ is not a real number. After converting into standard form, we must note that the term with i is only considered as the imaginary part. As there is no term with i, the imaginary part will be zero.
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