
If Young’s modulus for steel is , then how much weight be suspended from a steel wire of length and diameter so that the length of the wire be increased by ? ( )
Answer
516.3k+ views
1 likes
Hint: You can explain in brief what Hooke’s law states with its equation, i.e. Strain Stress. Then write down this equation in terms of linear extension . Then calculate the stress using the equation Stress and the strain using the equation Strain . Then put these values in the equation and then use the equation to reach the solution.
Complete step-by-step solution:
The Young modulus is based on Hooke’s law
According to Hooke’s law, the strain in a material is directly proportional to the stress applied.
Strain Stress
…………….....(Equation 1)
Here, Young’s modulus
The above equation is just for the linear extension of material, we have different equations for the areal and volumetric extension of a material.
Given in the problem
Radius
Now we know that,
Stress
Here, Force
Area of cross-section
We also know that
Strain
Here, Change in the length of the wire
The original length of the wire
Substituting the values of stress and strain in equation 1, we get
Let be the weight suspended from the wire
Hence, a weight should be suspended from a steel wire of length and diameter so that the length of the wire increases by .
Note: While attempting this solution, it was assumed that the wire would follow Hooke’s law (the strain will increase at a constant rate with the strain). But in reality, any material follows Hooke’s law for a certain range of stress, and stress and outside of this range strain do not remain directly proportional to stress. Even if Hooke’s law is followed if we keep on stretching the wire we will reach a point where the strain would become so large that the wire would break in two.
Complete step-by-step solution:
The Young modulus is based on Hooke’s law
According to Hooke’s law, the strain in a material is directly proportional to the stress applied.
Strain
Here,
The above equation is just for the linear extension of material, we have different equations for the areal and volumetric extension of a material.
Given in the problem
Radius
Now we know that,
Stress
Here,
We also know that
Strain
Here,
Substituting the values of stress and strain in equation 1, we get
Let
Hence, a
Note: While attempting this solution, it was assumed that the wire would follow Hooke’s law (the strain will increase at a constant rate with the strain). But in reality, any material follows Hooke’s law for a certain range of stress, and stress and outside of this range strain do not remain directly proportional to stress. Even if Hooke’s law is followed if we keep on stretching the wire we will reach a point where the strain would become so large that the wire would break in two.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
The flightless birds Rhea Kiwi and Emu respectively class 11 biology CBSE

1 litre is equivalent to A 1000mL B 100cm3 C 10mL D class 11 physics CBSE

A car travels 100 km at a speed of 60 kmh and returns class 11 physics CBSE

Name the Largest and the Smallest Cell in the Human Body ?

Explain zero factorial class 11 maths CBSE

In tea plantations and hedge making gardeners trim class 11 biology CBSE
