
If the value of a polynomial \[{{x}^{2}}-mx+7\] is \[35\], when \[x=2\] then find m.
A. \[m=2\]
B. \[m=-12\]
C. \[m=-2\]
D. \[m=7\]
Answer
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Hint: The quadratic equation is given and one of the values of x is also given, so for this type of problem to solve we have to substitute the value of x and solve the equation and find the value of x. Substitute \[x=2\] in \[{{x}^{2}}-mx+7\]= 35 and get the value of m.
Complete step-by-step solution -
Given equation is \[{{x}^{2}}-mx+7=35\]. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (1)
This is a quadratic equation.
Given \[x=2\] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (2)
Substitute (2) in (1) we get,
\[{{2}^{2}}-2m+7=35\]
By further solving we get,
\[4-2m+7=35\]
By further solving we get,
\[-2m=35-11\]
By further solving we get,
\[2m=-24\]
By further solving we get,
\[m=-12\].
Therefore the answer is option B.
Note: This is a direct problem. We get the solution just by substituting the given value and doing some mathematical operations. As the problem is easy to solve but take care during calculation.
Complete step-by-step solution -
Given equation is \[{{x}^{2}}-mx+7=35\]. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (1)
This is a quadratic equation.
Given \[x=2\] . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (2)
Substitute (2) in (1) we get,
\[{{2}^{2}}-2m+7=35\]
By further solving we get,
\[4-2m+7=35\]
By further solving we get,
\[-2m=35-11\]
By further solving we get,
\[2m=-24\]
By further solving we get,
\[m=-12\].
Therefore the answer is option B.
Note: This is a direct problem. We get the solution just by substituting the given value and doing some mathematical operations. As the problem is easy to solve but take care during calculation.
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