Question

If the upper and the lower limits of a class interval are 16 and 10, the class-interval is?
A.10-16
B.16-10
C.10-16 or 16-10
D.None of these

Answer 1

Hint: First we will use the formula to calculate the class interval is \[{\text{Lower Limit}} - {\text{Upper Limit}}\]. Then we will substitute 16 for lower limit and 10 for upper limit in the given formula to find the value of class interval.

Complete step-by-step answer:
We are given that the upper limit is 16 and lower limit is 10.
We know that the upper limit of a class interval is the maximum value of that interval and the lower limit of a class interval is the minimum value of that interval.
We know that the formula to calculate the class interval is \[{\text{Lower Limit}} - {\text{Upper Limit}}\].
Finding the value of lower limit and upper limit from the given class interval, we get
\[{\text{Lower Limit}} = 16\]
\[{\text{Upper Limit}} = 10\]
Substituting the value of lower limit and upper limit in the above class mark, we get
\[ \Rightarrow {\text{Class Interval}} = 16 - 10\]
Therefore, the value of the class interval is \[16 - 10\].
Hence, option A is correct.

Note: We know that a statistics value within a class interval, especially its midpoint or the nearest integral value, used to represent the interval for computational convenience. Write the values from the question properly and avoid calculation mistakes. Do not get confused by misplacing lower limit with upper limit and upper limit with lower limit.