Question

If the supply of oxygen is limited, $ {H_2}S $ reacts with $ {O_2} $ to form:
(A) $ {H_2}O + S{O_3} $
(B) $ {H_2}O + S $
(C) $ {H_2}S{O_4} + S $
(D) $ {H_2}O + S{O_2} $

Answer 1

Hint: it is colourless, flammable, toxic and corrosive in nature. we can say that the hydrogen sulphide burns with a blue flame to given sulphur dioxide and water but here in the question it is given that the limited supply of oxygen is gives the water along with sulphur

Complete step by step answer
Firstly we will talk about the hydrogen sulphide gas so we come to know that it is basically found during the drilling and the production of the crude oil and the natural gas. It is also produced by the microbial breakdown of the organic materials in the absence of oxygen. So it is colourless, flammable, toxic and corrosive in nature. we should further note here that the hydrogen sulphide is denser than the air. And we should note here that its mixture is explosive in nature. When the adequate amount of oxygen is provided then we can say that the hydrogen sulphide burns with a blue flame to given sulphur dioxide and water but here in the question it is given that the limited supply of oxygen is gives the water along with sulphur not the sulphur dioxide and this further marks a big difference with the oxygen supply. This can be further expressed through the equation:
 $ {H_2}S + {O_{2(LIMITED)}} \to {H_2}O + S $
Discussing more about it we can say that hydrogen sulphide acts as a weak acid on getting slightly soluble in water.

Hence, option B is correct.

Note
It is important to note here that the sulphur dioxide which is produced when an adequate supply of oxygen is given leads to the formation of sulphur and water when reacts further in the presence of a catalyst with hydrogen sulphite.