Question

If the number N when divided by 5 leaves a remainder 3, what might be the ones digit of N?
(A) 2
(B) 3
(C) 4
(D) 6

Answer 1

Hint: Here for answering these types of questions we need to observe the ones digit for general exact divisible numbers by 5 and we will add 3 to them and verify the options. Since we know that \[number=dividend\times divisor+remainder\]

Complete step-by-step answer:
The numbers which are exactly divisible by $5$ are $0, 5, 10, 15, 20, 25………….and\ so\ on$.
If we observe the above pattern that any number having $0$ or $5$ in the ones digit is exactly divisible by $5$.
So if we have a number $r$ as remainder then we are sure that it will be less than $5$ and now we can say that the number which leaves r as remainder will have $r+5$ or $r+0$ as the ones digit.
Here, in the question it is given that the number N when divided by 5 leaves a remainder 3.
So here we will have $3+5$ or $3+0$ as the ones digit for N.
Hence here we will have 3 or 8 as the ones digit for N.

So, the correct answer is “Option B”.

Note: For answering questions of these type it would be efficient if we remember the simply rules to find the perfect dividend of a divisor they are
(i) For 2 it should be even, that is it has 0, 2, 4, 6, 8 (any one) as the ones digit.
(ii) For 3 the sum of all digits of the number should be multiple of 3.
(iii) For 5 it should have 0, 5 as one digit.
(iv) For 6 it should be divisible by both 2 and 3.
(v) For 9 the sum of all digits of the number should be multiple of 9.
(vi) For 10 it should have 0 as one digit.
Similarly if observed we can get for all numbers.