If the mean of \[x\] and \[\dfrac{1}{x}\] is \[M\] , then the mean of \[{x^2}\] and \[\dfrac{1}{{{x^2}}}\] is
A.\[{M^2}\]
B.\[\dfrac{{{M^2}}}{4}\]
C.\[2{M^2} - 1\]
D.\[2{M^2} + 1\]
Answer
589.2k+ views
Hint: Here, we have to find the value of mean of \[{x^2}\] and \[\dfrac{1}{{{x^2}}}\]. The mean is defined as the average of a given set of numbers. Here we will first use the given mean and form an equation. Then we will simplify the equation and square the terms so that we get an equation containing the terms \[{x^2}\] and \[\dfrac{1}{{{x^2}}}\] . We will then simplify the equation to get the required mean.
Formula Used:
We will use the following formulas:
1. \[\overline x = \dfrac{1}{n}\left( {\sum\limits_{i = 1}^n {{x_i}} } \right) = \dfrac{{{x_1} + {x_2} + {x_3} + ...... + {x_n}}}{n}\], where \[{x_1},{x_2},{x_3},.......,{x_n}\] be the samples of data.
2.The square of the sum of two numbers is given by the algebraic identity \[{\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab\]
Complete step-by-step answer:
We know that the mean of \[x\] and \[\dfrac{1}{x}\] is \[M\].
Therefore,
\[\overline x = M\]
Substituting \[\overline x = \dfrac{{x + \dfrac{1}{x}}}{2}\] in the above equation, we get
\[ \Rightarrow \dfrac{{x + \dfrac{1}{x}}}{2} = M\]
On cross multiplication, we get
\[ \Rightarrow x + \dfrac{1}{x} = 2M\]
Squaring on both the sides, we get
\[ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^2} = {\left( {2M} \right)^2}\]
\[ \Rightarrow \left( {{x^2} + \dfrac{1}{{{x^2}}} + 2 \cdot x \cdot \dfrac{1}{x}} \right) = 4{M^2}\]
Simplifying the equation, we have
\[ \Rightarrow {x^2} + \dfrac{1}{{{x^2}}} + 2 = 4{M^2}\]
Rewriting the equation, we have
\[ \Rightarrow {x^2} + \dfrac{1}{{{x^2}}} = 4{M^2} - 2\]
Dividing by 2 on both the sides, we get
\[ \Rightarrow \dfrac{{{x^2} + \dfrac{1}{{{x^2}}}}}{2} = \dfrac{{4{M^2} - 2}}{2}\]
\[ \Rightarrow \dfrac{{{x^2} + \dfrac{1}{{{x^2}}}}}{2} = 2{M^2} - 1\]
Therefore, the mean of \[{x^2}\] and \[\dfrac{1}{{{x^2}}}\] is \[2{M^2} - 1\].
Note: We should note that there are three types of mean namely arithmetic mean (A.M.), weighted Arithmetic mean, Geometric mean (G.M.) and Harmonic mean (H.M) respectively. When some of the values are not important, then we assign them certain numerical values to show their relative importance. These numerical values are called weights. Thus the mean calculated is called weighted arithmetic mean. The geometric mean, G, of a set of n positive values \[{X_1},{\rm{ }}{X_2},{\rm{ }} \ldots \ldots ,{\rm{ }}{X_n}\] is the nth root of the product of the values. The harmonic mean, H, of a set of \[n\] values\[{X_1},{\rm{ }}{X_2},{\rm{ }} \ldots \ldots ,{\rm{ }}{X_n}\] is the reciprocal of the arithmetic mean of the reciprocals of the values.
Formula Used:
We will use the following formulas:
1. \[\overline x = \dfrac{1}{n}\left( {\sum\limits_{i = 1}^n {{x_i}} } \right) = \dfrac{{{x_1} + {x_2} + {x_3} + ...... + {x_n}}}{n}\], where \[{x_1},{x_2},{x_3},.......,{x_n}\] be the samples of data.
2.The square of the sum of two numbers is given by the algebraic identity \[{\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab\]
Complete step-by-step answer:
We know that the mean of \[x\] and \[\dfrac{1}{x}\] is \[M\].
Therefore,
\[\overline x = M\]
Substituting \[\overline x = \dfrac{{x + \dfrac{1}{x}}}{2}\] in the above equation, we get
\[ \Rightarrow \dfrac{{x + \dfrac{1}{x}}}{2} = M\]
On cross multiplication, we get
\[ \Rightarrow x + \dfrac{1}{x} = 2M\]
Squaring on both the sides, we get
\[ \Rightarrow {\left( {x + \dfrac{1}{x}} \right)^2} = {\left( {2M} \right)^2}\]
\[ \Rightarrow \left( {{x^2} + \dfrac{1}{{{x^2}}} + 2 \cdot x \cdot \dfrac{1}{x}} \right) = 4{M^2}\]
Simplifying the equation, we have
\[ \Rightarrow {x^2} + \dfrac{1}{{{x^2}}} + 2 = 4{M^2}\]
Rewriting the equation, we have
\[ \Rightarrow {x^2} + \dfrac{1}{{{x^2}}} = 4{M^2} - 2\]
Dividing by 2 on both the sides, we get
\[ \Rightarrow \dfrac{{{x^2} + \dfrac{1}{{{x^2}}}}}{2} = \dfrac{{4{M^2} - 2}}{2}\]
\[ \Rightarrow \dfrac{{{x^2} + \dfrac{1}{{{x^2}}}}}{2} = 2{M^2} - 1\]
Therefore, the mean of \[{x^2}\] and \[\dfrac{1}{{{x^2}}}\] is \[2{M^2} - 1\].
Note: We should note that there are three types of mean namely arithmetic mean (A.M.), weighted Arithmetic mean, Geometric mean (G.M.) and Harmonic mean (H.M) respectively. When some of the values are not important, then we assign them certain numerical values to show their relative importance. These numerical values are called weights. Thus the mean calculated is called weighted arithmetic mean. The geometric mean, G, of a set of n positive values \[{X_1},{\rm{ }}{X_2},{\rm{ }} \ldots \ldots ,{\rm{ }}{X_n}\] is the nth root of the product of the values. The harmonic mean, H, of a set of \[n\] values\[{X_1},{\rm{ }}{X_2},{\rm{ }} \ldots \ldots ,{\rm{ }}{X_n}\] is the reciprocal of the arithmetic mean of the reciprocals of the values.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

