
If the line and are concurrent, then is.
A. 1
B. -1
C. 25
D. 5
Answer
543.3k+ views
1 likes
Hint: If three lines and are concurrent then the determinant will equal to zero.
Solve the determinant and get the value of ’k’.
Complete step-by-step answer:
As, we know that concurrent means have only one intersection point. So, if three lines are concurrent, then they should meet at only one point.
Now, condition for concurrency of three lines are
and can be given as
……………………………………………………………….(i)
So, now we have lines given as
and
or
and
Now, we can compare the above lines with the mentioned lines in starting of solution and get the values of , and .
Hence, we can form a determinant as given in equation as
Now, let us expand the determinant through Row 1. And hence, we get
On simplifying the above equation, we get
And hence, we get
Hence, if the given lines in the problem is constant, then value k should be 25.
Therefore option (C) is correct.
Note: Another approach for getting value of k that we can solve first and third equation to get value of ‘ ’ and ‘ ’ and now put it with line second to get ‘k’ as all three lines have same intersecting point by definition of concurrency of lines.
One can go wrong if put in the determinant as line is not in the standard form i.e. . So, first write it in the standard form then substitute the values in the determinant. Hence, should be ‘-k ’ according to the standards.
Determinant used in the solution can be proved by using the formula of the area of the triangle.
The area formed with the concurrent lines should be zero. Hence, one can get the same determinant as given in the solution.
Solve the determinant and get the value of ’k’.
Complete step-by-step answer:
As, we know that concurrent means have only one intersection point. So, if three lines are concurrent, then they should meet at only one point.
Now, condition for concurrency of three lines are
So, now we have lines given as
or
and
Now, we can compare the above lines with the mentioned lines in starting of solution and get the values of

Hence, we can form a determinant as given in equation as
Now, let us expand the determinant through Row 1. And hence, we get
On simplifying the above equation, we get
And hence, we get
Hence, if the given lines in the problem is constant, then value k should be 25.
Therefore option (C) is correct.
Note: Another approach for getting value of k that we can solve first and third equation to get value of ‘
One can go wrong if put
Determinant used in the solution can be proved by using the formula of the area of the triangle.
The area formed with the concurrent lines should be zero. Hence, one can get the same determinant as given in the solution.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Trending doubts
What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

What are saprophytes Give two examples class 12 biology CBSE

How do you convert from joules to electron volts class 12 physics CBSE

Mirage is a phenomena due to A Refraction of light class 12 physics CBSE

Why did French artist Frederic sorrieu prepare a series class 12 social science CBSE

What is Nutrition Explain Diff Type of Nutrition ?
