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In the question, it is asking for the area enclosed by the broad lines which encloses some full squares and some half-squares. So, first, we need to determine the total number of full squares and the total number of half squares, and to get the result, add them up to get the total number of full squares such that the area of a square is 10 square units.

Here, the area enclosed by the broad line is to be determined in which 4 complete squares are enclosed along with 2 half-squares such that in total of 5 complete squares are enclosed.

As the area enclosed by one square is 1 square unit then, the area enclosed by 5 squares will be:

$

A = 5 \times 1 \\

= 5{\text{ square units}} \\

$

Hence, the area enclosed by the broad line is 5 square units.