If \[\left| {\overrightarrow a } \right| = 2,\left| {\overrightarrow b } \right| = 3\] and \[\left| {2\overrightarrow a - \overrightarrow b } \right| = 5\], then \[\left| {2\overrightarrow a + \overrightarrow b } \right|\] equals
(A) 17
(B) 7
(C) 5
(D) 1
Answer
649.8k+ views
Hint: Here first we will use the given quantity i.e. \[\left| {2\overrightarrow a - \overrightarrow b } \right| = 5\] and square both the sides and expand the resultant quantity.
Then put the known values to and find the value of the required quantity.
Complete step-by-step answer:
It is given that:
\[\left| {2\overrightarrow a - \overrightarrow b } \right| = 5\]
Squaring both the sides we get:-
\[{\left( {\left| {2\overrightarrow a - \overrightarrow b } \right|} \right)^2} = {\left( 5 \right)^2}\]
Solving it further we get:-
\[\left| {2\overrightarrow a - \overrightarrow b } \right|.\left| {2\overrightarrow a - \overrightarrow b } \right| = 25\]
Now on multiplying we get:-
\[\left( 2 \right)\left( 2 \right)\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( 1 \right)\left( 1 \right)\left( {{{\left| {\overrightarrow b } \right|}^2}} \right) - 2\left( {\overrightarrow a .\overrightarrow b } \right) - 2\left( {\overrightarrow a .\overrightarrow b } \right) = 25\]
Simplifying it further we get:-
\[4\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( {{{\left| {\overrightarrow b } \right|}^2}} \right) - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25\]
Now it is given that:
\[\left| {\overrightarrow a } \right| = 2,\left| {\overrightarrow b } \right| = 3\]
Hence putting in the known values we get:-
\[4{\left( 2 \right)^2} + {\left( 3 \right)^2} - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25\]
Now solving it further we get:-
\[
4\left( 4 \right) + 9 - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 \\
\Rightarrow 16 + 9 - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 \\
\Rightarrow 25 - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 \\
\]
Evaluating the value of \[4\left( {\overrightarrow a .\overrightarrow b } \right)\] we get:-
\[
4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 - 25 \\
4\left( {\overrightarrow a .\overrightarrow b } \right) = 0...............................\left( 1 \right) \\
\]
Now we will evaluate the value of \[\left| {2\overrightarrow a + \overrightarrow b } \right|\].
On squaring the give quantity we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = \left( {2\overrightarrow a + \overrightarrow b } \right).\left( {2\overrightarrow a + \overrightarrow b } \right)\]
Solving it further we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = \left( 2 \right)\left( 2 \right)\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( 1 \right)\left( 1 \right)\left( {{{\left| {\overrightarrow b } \right|}^2}} \right) + 2\left( {\overrightarrow a .\overrightarrow b } \right) + 2\left( {\overrightarrow a .\overrightarrow b } \right)\]
On simplifying we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( {{{\left| {\overrightarrow b } \right|}^2}} \right) + 4\left( {\overrightarrow a .\overrightarrow b } \right)\]
Now it is given that:
\[\left| {\overrightarrow a } \right| = 2,\left| {\overrightarrow b } \right| = 3\]
Hence putting in the known values we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4{\left( 2 \right)^2} + {\left( 3 \right)^2} - 4\left( {\overrightarrow a .\overrightarrow b } \right)\]
Now putting the value from equation1 we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4{\left( 2 \right)^2} + {\left( 3 \right)^2} - 0\]
Solving it further we get:-
\[
{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4\left( 4 \right) + 9 \\
\Rightarrow {\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 16 + 9 \\
\Rightarrow {\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 25 \\
\]
Now taking square root of both the sides we get:-
\[\sqrt {{{\left| {2\overrightarrow a + \overrightarrow b } \right|}^2}} = \sqrt {25} \]
Evaluating it further we get:-
\[\left| {2\overrightarrow a + \overrightarrow b } \right| = \pm 5\]
But since we know that the modulus of any quantity is always positive
Hence we will consider the positive value
Therefore,
\[\left| {2\overrightarrow a + \overrightarrow b } \right| = 5\]
Hence option C is the correct option.
Note: Students should keep in mind that modulus of any quantity is always positive and also when we take squares of any vector quantity then they are multiplied with each other using dot product.
Then put the known values to and find the value of the required quantity.
Complete step-by-step answer:
It is given that:
\[\left| {2\overrightarrow a - \overrightarrow b } \right| = 5\]
Squaring both the sides we get:-
\[{\left( {\left| {2\overrightarrow a - \overrightarrow b } \right|} \right)^2} = {\left( 5 \right)^2}\]
Solving it further we get:-
\[\left| {2\overrightarrow a - \overrightarrow b } \right|.\left| {2\overrightarrow a - \overrightarrow b } \right| = 25\]
Now on multiplying we get:-
\[\left( 2 \right)\left( 2 \right)\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( 1 \right)\left( 1 \right)\left( {{{\left| {\overrightarrow b } \right|}^2}} \right) - 2\left( {\overrightarrow a .\overrightarrow b } \right) - 2\left( {\overrightarrow a .\overrightarrow b } \right) = 25\]
Simplifying it further we get:-
\[4\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( {{{\left| {\overrightarrow b } \right|}^2}} \right) - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25\]
Now it is given that:
\[\left| {\overrightarrow a } \right| = 2,\left| {\overrightarrow b } \right| = 3\]
Hence putting in the known values we get:-
\[4{\left( 2 \right)^2} + {\left( 3 \right)^2} - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25\]
Now solving it further we get:-
\[
4\left( 4 \right) + 9 - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 \\
\Rightarrow 16 + 9 - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 \\
\Rightarrow 25 - 4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 \\
\]
Evaluating the value of \[4\left( {\overrightarrow a .\overrightarrow b } \right)\] we get:-
\[
4\left( {\overrightarrow a .\overrightarrow b } \right) = 25 - 25 \\
4\left( {\overrightarrow a .\overrightarrow b } \right) = 0...............................\left( 1 \right) \\
\]
Now we will evaluate the value of \[\left| {2\overrightarrow a + \overrightarrow b } \right|\].
On squaring the give quantity we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = \left( {2\overrightarrow a + \overrightarrow b } \right).\left( {2\overrightarrow a + \overrightarrow b } \right)\]
Solving it further we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = \left( 2 \right)\left( 2 \right)\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( 1 \right)\left( 1 \right)\left( {{{\left| {\overrightarrow b } \right|}^2}} \right) + 2\left( {\overrightarrow a .\overrightarrow b } \right) + 2\left( {\overrightarrow a .\overrightarrow b } \right)\]
On simplifying we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4\left( {{{\left| {\overrightarrow a } \right|}^2}} \right) + \left( {{{\left| {\overrightarrow b } \right|}^2}} \right) + 4\left( {\overrightarrow a .\overrightarrow b } \right)\]
Now it is given that:
\[\left| {\overrightarrow a } \right| = 2,\left| {\overrightarrow b } \right| = 3\]
Hence putting in the known values we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4{\left( 2 \right)^2} + {\left( 3 \right)^2} - 4\left( {\overrightarrow a .\overrightarrow b } \right)\]
Now putting the value from equation1 we get:-
\[{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4{\left( 2 \right)^2} + {\left( 3 \right)^2} - 0\]
Solving it further we get:-
\[
{\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 4\left( 4 \right) + 9 \\
\Rightarrow {\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 16 + 9 \\
\Rightarrow {\left| {2\overrightarrow a + \overrightarrow b } \right|^2} = 25 \\
\]
Now taking square root of both the sides we get:-
\[\sqrt {{{\left| {2\overrightarrow a + \overrightarrow b } \right|}^2}} = \sqrt {25} \]
Evaluating it further we get:-
\[\left| {2\overrightarrow a + \overrightarrow b } \right| = \pm 5\]
But since we know that the modulus of any quantity is always positive
Hence we will consider the positive value
Therefore,
\[\left| {2\overrightarrow a + \overrightarrow b } \right| = 5\]
Hence option C is the correct option.
Note: Students should keep in mind that modulus of any quantity is always positive and also when we take squares of any vector quantity then they are multiplied with each other using dot product.
Recently Updated Pages
Lysosomes are known as suicidal bags of cell why class 11 biology CBSE

Father s age is three times the sum of the ages of-class-11-maths-CBSE

Give a comparative account of the classes of kingdom class 11 biology CBSE

The ceiling of a long hall is 25m high What is the class 11 physics CBSE

Name the Largest and the Smallest Cell in the Human Body ?

Draw a welllabelled diagram of a plant cell class 11 biology CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

10 examples of diffusion in everyday life

