Question

If brown eye color is dominant over Blue, the chances of the blue-eyed child between blue-eyed man and brown-eyed daughter of a blue-eyed woman is
(a) Nil
(b) 25%
(c) 50%
(d) 100%

Answer 1

Hint: Genes come in various varieties, called alleles. Somatic cells contain two alleles for each and every gene, with one allele, given by each parent of an organism. Regularly, it is difficult to figure out which two alleles of a gene are available inside an organism's chromosomes dependent solely on the outward appearance of that organism.

Complete answer:
In the given problem, the brown eye (BB) color is dominant over blue eye (bb) color. For recessive genes inherited from the mother, the brown-eyed daughter of blue-eyed (bb) women will have genotype Bb. On the off chance that a blue-eyed (bb) man marries a brown-eyed (Bb) female, the offspring will be brown-eyed (Bb) or blue-eyed (bb) in a proportion of 1:1.
This is because offspring will get only one type of recessive gene from the father. Hence, the chances of a blue-eyed child of this couple are 50%.

Additional Information: Genetic traits can be passed from parent to child in various manners. As you will see, individuals can convey a gene however not be affected directly by it themselves.
Our genes are grouped into collections called chromosomes. Most people have 46 chromosomes, in 23 pairs. X and Y are one of the pairs in the sex chromosomes. Our sex chromosomes contain the genes that characterize you male or female. Men have an X and Y chromosomes and women have two X chromosomes. The rest of your chromosomes are called autosomal chromosomes.
So the correct answer is ‘50%’.

Note: If the mother is a carrier and the father has the condition, then there is a 1 in 2 chance (50%) that a daughter would be affected. From her dad, she would consistently get the gene that doesn't work appropriately, yet she may get the working gene from her mom.