Answer
Verified
396k+ views
Hint: To solve this question, we will use these formulas. The Cartesian product of two sets P and Q is given by,
\[\text{P}\times \text{Q=}\left\{ \left( p,q \right) \right\}:p\in P,q\in Q\]
And subtraction of two sets P and Q is given by,
\[P-Q=\left\{ x:x\in P\text{ and x}\notin \text{Q} \right\}\]
Complete step-by-step answer:
Given that, \[\text{A=}\left\{ 1,2,3 \right\},\text{ B=}\left\{ 4 \right\},\text{ C=}\left\{ 5 \right\}\]
We will separately calculate \[\left( \text{A}\times \text{B} \right),\left( \text{A}\times C \right)\text{ and }\left( \text{B-C} \right)\] first. The Cartesian product of two sets P and Q is given by;
\[\text{P}\times \text{Q=}\left\{ \left( p,q \right) \right\}:p\in P,q\in Q\]
And subtraction of two sets P and Q is given by,
\[P-Q=\left\{ x:x\in P\text{ and x}\notin \text{Q} \right\}\]
The possible combination of $A\times B$ using the above formula is given by;
\[A\times B=\left\{ \left( 1,4 \right),\left( 2,4 \right),\left( 3,4 \right) \right\}\]
The possible combination of $A\times C$ using the above formula is given by;
\[A\times C=\left\{ \left( 1,5 \right),\left( 2,5 \right),\left( 3,5 \right) \right\}\]
The possible value of B-C using the above formula of difference of two set is given by;
\[B-C=\varnothing \text{ (empty set)}\]
Now, the value of $A\times \left( B-C \right)$ using the above formula is $\varnothing $ as there is no element in B-C. So, $A\times \left( B-C \right)$ is also an empty set.
Now, consider \[\left( \text{A}\times \text{B} \right)-\left( \text{A}\times C \right)\]
Using the formula of difference of set stated above, we get:
\[\left( \text{A}\times \text{B} \right)-\left( \text{A}\times C \right)=\left\{ \left( 1,4 \right),\left( 2,4 \right),\left( 3,4 \right) \right\}-\left\{ \left( 1,5 \right),\left( 2,5 \right)\left( 3,5 \right) \right\}=\varnothing \]
As there is no common element. Hence, the value of \[\text{A}\times \left( \text{B-C} \right)=\left( \text{A}\times \text{B} \right)-\left( \text{A}\times C \right)=\varnothing \]
Hence verified.
Note: The biggest possibility of mistake which the students make while solving this question is considering \[\text{A}\times \left( \text{B-C} \right)=\left\{ \left( 1,0 \right),\left( 2,0 \right),\left( 3,0 \right) \right\}\] This step is wrong, because 0 and $\varnothing $ are different elements, here \[B-C=\varnothing \text{ (empty set)}\] and not 0. Therefore, \[\text{A}\times \left( \text{B-C} \right)=\left\{ \left( 1,0 \right),\left( 2,0 \right),\left( 3,0 \right) \right\}\] is wrong as \[0\notin B-C\]
\[\text{P}\times \text{Q=}\left\{ \left( p,q \right) \right\}:p\in P,q\in Q\]
And subtraction of two sets P and Q is given by,
\[P-Q=\left\{ x:x\in P\text{ and x}\notin \text{Q} \right\}\]
Complete step-by-step answer:
Given that, \[\text{A=}\left\{ 1,2,3 \right\},\text{ B=}\left\{ 4 \right\},\text{ C=}\left\{ 5 \right\}\]
We will separately calculate \[\left( \text{A}\times \text{B} \right),\left( \text{A}\times C \right)\text{ and }\left( \text{B-C} \right)\] first. The Cartesian product of two sets P and Q is given by;
\[\text{P}\times \text{Q=}\left\{ \left( p,q \right) \right\}:p\in P,q\in Q\]
And subtraction of two sets P and Q is given by,
\[P-Q=\left\{ x:x\in P\text{ and x}\notin \text{Q} \right\}\]
The possible combination of $A\times B$ using the above formula is given by;
\[A\times B=\left\{ \left( 1,4 \right),\left( 2,4 \right),\left( 3,4 \right) \right\}\]
The possible combination of $A\times C$ using the above formula is given by;
\[A\times C=\left\{ \left( 1,5 \right),\left( 2,5 \right),\left( 3,5 \right) \right\}\]
The possible value of B-C using the above formula of difference of two set is given by;
\[B-C=\varnothing \text{ (empty set)}\]
Now, the value of $A\times \left( B-C \right)$ using the above formula is $\varnothing $ as there is no element in B-C. So, $A\times \left( B-C \right)$ is also an empty set.
Now, consider \[\left( \text{A}\times \text{B} \right)-\left( \text{A}\times C \right)\]
Using the formula of difference of set stated above, we get:
\[\left( \text{A}\times \text{B} \right)-\left( \text{A}\times C \right)=\left\{ \left( 1,4 \right),\left( 2,4 \right),\left( 3,4 \right) \right\}-\left\{ \left( 1,5 \right),\left( 2,5 \right)\left( 3,5 \right) \right\}=\varnothing \]
As there is no common element. Hence, the value of \[\text{A}\times \left( \text{B-C} \right)=\left( \text{A}\times \text{B} \right)-\left( \text{A}\times C \right)=\varnothing \]
Hence verified.
Note: The biggest possibility of mistake which the students make while solving this question is considering \[\text{A}\times \left( \text{B-C} \right)=\left\{ \left( 1,0 \right),\left( 2,0 \right),\left( 3,0 \right) \right\}\] This step is wrong, because 0 and $\varnothing $ are different elements, here \[B-C=\varnothing \text{ (empty set)}\] and not 0. Therefore, \[\text{A}\times \left( \text{B-C} \right)=\left\{ \left( 1,0 \right),\left( 2,0 \right),\left( 3,0 \right) \right\}\] is wrong as \[0\notin B-C\]
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Write an application to the principal requesting five class 10 english CBSE
Difference Between Plant Cell and Animal Cell
a Tabulate the differences in the characteristics of class 12 chemistry CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
Discuss what these phrases mean to you A a yellow wood class 9 english CBSE
List some examples of Rabi and Kharif crops class 8 biology CBSE