
If a:b = 2:1, b:c = 1:3, c:d = 2:3 and d:e = 1:2, find a:b:c:d:e.
Answer
510k+ views
Hint: This a question of ratio and proportions. The concept of ratio is similar to division. The first number is taken as numerator and second as denominator. For example-
X:Y = 1:2 is the same as $\dfrac{\mathrm X}{\mathrm Y}=\dfrac12$
Complete step by step answer:
To solve this problem, find all the variables in terms of one variable(say a), and then write them in a ratio so that the common variable gets cancelled.
Now, we are given the ratios, so we will first convert them into fractions-
$\dfrac{\mathrm a}{\mathrm b}=2\\\mathrm a=2\mathrm b....\left(1\right)\\\dfrac{\mathrm b}{\mathrm c}=\dfrac13\\\mathrm c=3\mathrm b....\left(2\right)\\\dfrac{\mathrm c}{\mathrm d}=\dfrac23\\\mathrm d=\dfrac32\mathrm c\\\mathrm{Using}\;\mathrm{equation}\left(2\right),\;\\\mathrm d=\dfrac32\times3\mathrm b=\dfrac92\mathrm b....\left(3\right)\\\dfrac{\mathrm d}{\mathrm e}=\dfrac12\\\mathrm e=2\mathrm d\\\mathrm{Using}\;\mathrm{equation}\left(3\right),\;\\\mathrm e=2\times\dfrac92\mathrm b=9\mathrm b....\left(4\right)\\\;$
We have to find a:b:c:d:e. Using equations (1), (2), (3) and (4), we can write that-
$\mathrm a:\mathrm b:\mathrm c:\mathrm d:\mathrm e=2\mathrm b:\mathrm b:3\mathrm b:\frac92\mathrm b:9\mathrm b\\\mathrm{Since}\;\mathrm b\;\mathrm{is}\;\mathrm{common},\;\mathrm{it}\;\mathrm{can}\;\mathrm{be}\;\mathrm{elIminated}.\\\mathrm a:\mathrm b:\mathrm c:\mathrm d:\mathrm e=2:1:3:\frac92:9\\\mathrm{To}\;\mathrm{simplify}\;\mathrm{the}\;\mathrm{answer}\;\mathrm{we}\;\mathrm{can}\;\mathrm{multiply}\;\mathrm{all}\;\mathrm{the}\;\mathrm{terms}\;\mathrm{by}\;2\\\mathrm a:\mathrm b:\mathrm c:\mathrm d:\mathrm e=4:2:6:9:18$
This is the required answer.
Note: Instead of b, any other variable can be taken as reference. A common mistake is that the students don't simplify the final answer and leave it in fractional form, which is incorrect. To simplify the ratio, one can multiply the whole ratio by the LCM of the denominators.
X:Y = 1:2 is the same as $\dfrac{\mathrm X}{\mathrm Y}=\dfrac12$
Complete step by step answer:
To solve this problem, find all the variables in terms of one variable(say a), and then write them in a ratio so that the common variable gets cancelled.
Now, we are given the ratios, so we will first convert them into fractions-
$\dfrac{\mathrm a}{\mathrm b}=2\\\mathrm a=2\mathrm b....\left(1\right)\\\dfrac{\mathrm b}{\mathrm c}=\dfrac13\\\mathrm c=3\mathrm b....\left(2\right)\\\dfrac{\mathrm c}{\mathrm d}=\dfrac23\\\mathrm d=\dfrac32\mathrm c\\\mathrm{Using}\;\mathrm{equation}\left(2\right),\;\\\mathrm d=\dfrac32\times3\mathrm b=\dfrac92\mathrm b....\left(3\right)\\\dfrac{\mathrm d}{\mathrm e}=\dfrac12\\\mathrm e=2\mathrm d\\\mathrm{Using}\;\mathrm{equation}\left(3\right),\;\\\mathrm e=2\times\dfrac92\mathrm b=9\mathrm b....\left(4\right)\\\;$
We have to find a:b:c:d:e. Using equations (1), (2), (3) and (4), we can write that-
$\mathrm a:\mathrm b:\mathrm c:\mathrm d:\mathrm e=2\mathrm b:\mathrm b:3\mathrm b:\frac92\mathrm b:9\mathrm b\\\mathrm{Since}\;\mathrm b\;\mathrm{is}\;\mathrm{common},\;\mathrm{it}\;\mathrm{can}\;\mathrm{be}\;\mathrm{elIminated}.\\\mathrm a:\mathrm b:\mathrm c:\mathrm d:\mathrm e=2:1:3:\frac92:9\\\mathrm{To}\;\mathrm{simplify}\;\mathrm{the}\;\mathrm{answer}\;\mathrm{we}\;\mathrm{can}\;\mathrm{multiply}\;\mathrm{all}\;\mathrm{the}\;\mathrm{terms}\;\mathrm{by}\;2\\\mathrm a:\mathrm b:\mathrm c:\mathrm d:\mathrm e=4:2:6:9:18$
This is the required answer.
Note: Instead of b, any other variable can be taken as reference. A common mistake is that the students don't simplify the final answer and leave it in fractional form, which is incorrect. To simplify the ratio, one can multiply the whole ratio by the LCM of the denominators.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Trending doubts
A number is chosen from 1 to 20 Find the probabili-class-10-maths-CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What are the public facilities provided by the government? Also explain each facility

Difference between mass and weight class 10 physics CBSE
