Question

If a perpendicular distance of a point \[P\] from the \[{x \ axis}\] is \[5 \ units\] and the foot of the perpendicular lies on the negative direction of the \[{x \ axis}\]. The point \[P\] has

Answer 1

Hint: In the given question, it’s given that the perpendicular distance of a point \[P\] from the \[{x \ axis}\] has \[5 \ units\]. We need to find the coordinate of P in this question.Perpendicular distance is nothing but the shortest distance from the point to the line.

Complete answer:We know that the perpendicular distance of a point from the \[{x \ axis}\] gives \[{x \ axis}\] coordinate of that point .
.i.e). \[x\] coordinate is always perpendicular to the \[{y \ axis}\]

Here the foot of the perpendicular lies in the negative direction of \[{ x \ axis}\], so the perpendicular distance can be measured in ll quadrant or lll quadrant.
From this we can conclude that the point \[P\] has \[y\] co-ordinate \[= 5 \ or \ - 5\]
The point \[P\] has ordinate \[= \ 5\ or\ - 5\]
Final answer :
The point \[P\] has ordinate \[= \ 5\ or\ - 5\]

Note:
The shortest distance of one point from the plane is called the perpendicular distance of that point. Basically there are two methods to calculate the perpendicular distance of a point . They are
-Vector method
-Cartesian method
We need to be careful that by mistake we might think the \[\ y \] -coordinate is the perpendicular distance from the \[y \] -axis but it is not, the \[x \] -coordinate is the perpendicular distance from the \[y \]- axis. First we need to know that the horizontal axis is known as \[x\] axis and the vertical axis is known as the \[y\] axis.