Question

If \[9ATP\] and \[6NADPH\] are utilized for photosynthetic carbon assimilation through the Calvin cycle, what would be the ratio of erythrose\[ 4\]- phosphate, xylulose\[ 5\]- phosphate, and ribulose \[ 5\]- phosphate molecules formed as intermediates in the regeneration phase of the Calvin cycle?
A. \[3:1:2\]
B. \[2:2:1\]
C. \[2:3:1\]
D. \[1:2:3\]

Answer 1

Hint:
The photosynthesis in prokaryotes occurs by two general methods- light-dependent reactions and the Calvin cycle, which initiates in the chloroplasts.
You may have seen that the general response for photosynthesis:
\[6C{O_2} + 6{H_2}O \to {C_6}{H_{12}}{O_6} + 6{O_2}\]
is the converse of the general response for cell respiration:
\[6{O_2} + {C_6}{H_{12}}{O_6} \to 6C{O_2} + 6{H_2}O\]
Photosynthesis produces oxygen as a result, and respiration produces carbon dioxide as a side-effect.

Complete answer:
The regeneration stage can be separated into steps.

Triosephosphate isomerase changes over the entirety of the \[G3P\] reversibly into dihydroxyacetone phosphate (DHAP), additionally a 3-carbon atom.
\[Aldolase and fructose - 1,6 - bisphosphatase\] convert a \[G3P\] and a DHAP into fructose \[6\] -phosphate (\[6C\]). A phosphate particle is lost into the arrangement.
At that point, the fixation of another \[C{O_2}\] creates two more \[G3P\].
F6P has two carbons eliminated by transketolase, giving erythrose-\[4\] phosphate. The two carbons on transketolase are added to a \[G3P\], giving the ketose xylulose- \[ 5\] -phosphate (\[Xu5P\]).
E4P and a DHAP (framed from one of the \[G3P\]from the subsequent \[C{O_2}\] fixation) are changed over into sedoheptulose\[ - 1,7 - \]bisphosphate (\[7\]C) by aldolase protein.
Sedoheptulose\[ - 1,7 - \]bisphosphatase (one of just three proteins of the Calvin cycle that are extraordinary to plants) cuts sedoheptulose\[ - 1,7 - \]bisphosphate into sedoheptulose-\[7\]-phosphate, delivering an inorganic phosphate particle into the arrangement.
Regeneration of a third \[C{O_2}\]

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Creates two more \[G3P\]. The ketose \[S7P\] has two carbons eliminated by transketolase, giving ribose-5-phosphate (R5P), and the two carbons staying on transketolase are moved to one of the \[G3P\], giving another Xu5P. This leaves one \[G3P\] due to an obsession of 3 \[C{O_2}\], with the age of three pentoses that can be changed over to Ru\[5\]P.
R5P is changed over into ribulose-\[5\]-phosphate (Ru\[5\]P, RuP) by phosphopeptide isomerase. Xu5P is changed over into RuP by phosphopentose epimerase.
Finally, phosphoribulokinase (another plant-interesting chemical of the pathway) phosphorylates RuP into RuBP, ribulose\[ - 1,5 - \]bisphosphate, finishing the Calvin cycle. This requires the contribution of one ATP.

Hence, the correct answer is option (D).

Note: Utilizing the energy transporters framed in the primary phase of photosynthesis, the Calvin cycle responses fix \[C{O_2}\]from the climate to assemble starch particles. A compound, RuBisCO, catalyzes the obsession response by joining \[C{O_2}\] with RuBP. The subsequent six-carbon mixture is separated into two three-carbon mixes, and the energy in ATP and NADPH is utilized to change over these atoms into \[G3P\].

Plants are equipped for both photosynthesis and cell respiration since they contain the two chloroplasts and mitochondria.