
If $ 4th $ July $ 1985 $ is Sunday than what day would be on $ 15th $ August $ 1986 $
A.Sunday
B.Saturday
C.Monday
D.Wednesday
Answer
489k+ views
Hint: Here we will use the concept of the leap year and the number of days in the year. Always remember a week has seven days and when the total number of days divided by seven gives a number of weeks.
Complete step-by-step answer:
For Non – leap year, when we move forward by one year then one more day is gained and vice-versa.
If $ 4th $ July $ 1985 $ is on Sunday then $ 4th $ July $ 1986 $ is on Monday (Since $ 1986 $ is also the non – leap year)
Leap year can be identified by dividing the year by the number and if the remainder is zero then that particular year is leap year and there will be $ 366 $ days in one year.
Now, when $ 4th $ July $ 1986 $ is on Monday then –
Now count the number of days from $ 4th $ July $ 1986 $ to $ 15th $ August $ 1986 $
It will be $ = (31 - 4) $ July days $ + 15 $ august days
Total $ = 27 + 15 $
Total $ = 42 $
Now, divide the above number by $ 7 $
$ = \dfrac{{42}}{7} = 6 $ weeks
So, there will be a complete six weeks and therefore the day on $ 15th $ August $ 1986 $ will be Monday.
Hence, from the given multiple choices – the option C is the correct answer.
So, the correct answer is “Option C”.
Note: Always remember that for any For Non – leap year, when we move forward by one year then one more day is gained and vice-versa. That is if Monday falls for the first year, then Tuesday falls for the same date for the next year. Remember the divisibility test for the number four to identify the leap year quickly.
Complete step-by-step answer:
For Non – leap year, when we move forward by one year then one more day is gained and vice-versa.
If $ 4th $ July $ 1985 $ is on Sunday then $ 4th $ July $ 1986 $ is on Monday (Since $ 1986 $ is also the non – leap year)
Leap year can be identified by dividing the year by the number and if the remainder is zero then that particular year is leap year and there will be $ 366 $ days in one year.
Now, when $ 4th $ July $ 1986 $ is on Monday then –
Now count the number of days from $ 4th $ July $ 1986 $ to $ 15th $ August $ 1986 $
It will be $ = (31 - 4) $ July days $ + 15 $ august days
Total $ = 27 + 15 $
Total $ = 42 $
Now, divide the above number by $ 7 $
$ = \dfrac{{42}}{7} = 6 $ weeks
So, there will be a complete six weeks and therefore the day on $ 15th $ August $ 1986 $ will be Monday.
Hence, from the given multiple choices – the option C is the correct answer.
So, the correct answer is “Option C”.
Note: Always remember that for any For Non – leap year, when we move forward by one year then one more day is gained and vice-versa. That is if Monday falls for the first year, then Tuesday falls for the same date for the next year. Remember the divisibility test for the number four to identify the leap year quickly.
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