
If 2-chloro 3-methylpentane is treated with ethanolic KOH solution. How many different alkenes would be formed via \[{E_2}\] elimination reaction?
Answer
557.4k+ views
Hint: In this reaction, we will see the \[\beta - \]hydrohalogenation. This means that a HX group will undergo this reaction and leave and give us different alkenes as products.
Complete step by step answer:
-In the \[{E_2}\] mechanism, a base abstracts a proton neighboring the leaving group, forcing the electrons down to make a double bond, and, in so doing, forcing off the leaving group.
-When numerous things happen simultaneously in a mechanism, such as the \[{E_2}\] reaction, it is called a concerted step.
-Now let us see the particular compound given to us:
So, now with the reaction with alcoholic KOH, if favours \[\beta - \]dehydrohalogenation.
-So now let us understand what is \[\beta - \]dehydrohalogenation. The \[\beta - \]positions to the halide group in the compounds are those carbons just next to them. The carbon containing Cl is \[\alpha \] carbon while the other two carbon on its left and right are \[\beta - \]carbons.
-Now, the elimination of -HX group should be from any of these \[\beta - \] carbons.
But how to decide?
-Thus, we follow Saytzeff's rule here.
-It states that more substituted alkene will always favour hydrogen elimination from that particular \[\beta - \] carbon which has a lesser number of hydrogens.
-Then, the products formed are:
-According to Satyzeff rule, we can see that in the major product the elimination occurred from the \[\beta - \]carbon containing a lesser number of hydrogens.
-Since, this is an \[{E_2}\] reaction, so no question of formation of carbocation. The intermediates form products.
Therefore, the correct answer is 4.
Note: Always follow Saytzeff rule when in \[{E_2}\] elimination. In \[{E_2}\], the steps are all concerted while for \[{E_1}\], the steps involving carbocation formations are more stepwise. It depends more on the stability of the carbocation but that is not the scene for \[{E_2}\] eliminations.
Complete step by step answer:
-In the \[{E_2}\] mechanism, a base abstracts a proton neighboring the leaving group, forcing the electrons down to make a double bond, and, in so doing, forcing off the leaving group.
-When numerous things happen simultaneously in a mechanism, such as the \[{E_2}\] reaction, it is called a concerted step.
-Now let us see the particular compound given to us:
So, now with the reaction with alcoholic KOH, if favours \[\beta - \]dehydrohalogenation.
-So now let us understand what is \[\beta - \]dehydrohalogenation. The \[\beta - \]positions to the halide group in the compounds are those carbons just next to them. The carbon containing Cl is \[\alpha \] carbon while the other two carbon on its left and right are \[\beta - \]carbons.
-Now, the elimination of -HX group should be from any of these \[\beta - \] carbons.
But how to decide?
-Thus, we follow Saytzeff's rule here.
-It states that more substituted alkene will always favour hydrogen elimination from that particular \[\beta - \] carbon which has a lesser number of hydrogens.
-Then, the products formed are:
-According to Satyzeff rule, we can see that in the major product the elimination occurred from the \[\beta - \]carbon containing a lesser number of hydrogens.
-Since, this is an \[{E_2}\] reaction, so no question of formation of carbocation. The intermediates form products.
Therefore, the correct answer is 4.
Note: Always follow Saytzeff rule when in \[{E_2}\] elimination. In \[{E_2}\], the steps are all concerted while for \[{E_1}\], the steps involving carbocation formations are more stepwise. It depends more on the stability of the carbocation but that is not the scene for \[{E_2}\] eliminations.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

