
Identify the terms, their coefficients for the following expression: $\dfrac{x}{2} + \dfrac{y}{2} - xy$.
A) Coefficient of $x$ in the term $\dfrac{x}{2}$ is $1$.
Coefficient of $y$ in the term $\dfrac{y}{2}$ is $1$.
Coefficient of $xy$ in the term $ - xy$ is $1$.
B) Coefficient of $x$ in the term $\dfrac{x}{2}$ is $1$.
Coefficient of $y$ in the term $\dfrac{y}{2}$ is $\dfrac{1}{2}$.
Coefficient of $xy$ in the term $ - xy$ is $1$.
C) Coefficient of $x$ in the term $\dfrac{x}{2}$ is $1$.
Coefficient of $y$ in the term $\dfrac{y}{2}$ is $1$.
Coefficient of $xy$ in the term $ - xy$ is $ - 1$.
D) Coefficient of $x$ in the term $\dfrac{x}{2}$ is $\dfrac{1}{2}$.
Coefficient of $y$ in the term $\dfrac{y}{2}$ is $\dfrac{1}{2}$.
Coefficient of $xy$ in the term $ - xy$ is $ - 1$.
Answer
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Hint: A coefficient is a number or constant that is multiplied to a variable that is present in an equation. Leaving all the variables in an operand, all constants left are the coefficients of a number. For example: The coefficient of ${x^2}$ in $2{x^2}$ is $2$.
Complete step by step solution:
We are given with an equation $\dfrac{x}{2} + \dfrac{y}{2} - xy$. Separating the variables and constants from each operand, we can write the equation as:
$\dfrac{x}{2} + \dfrac{y}{2} - xy$
$ \Rightarrow \dfrac{1}{2}x + \dfrac{1}{2}y - xy$ ……(1)
And, for the last operand we know that $ - x$ can be written as $\left( { - 1} \right)x$.
So, we can write the last operand $ - xy$ as $ + \left( { - xy} \right) = + \left( { - 1} \right)xy$.
Substituting this value in the equation 1, we get:
$ \Rightarrow \dfrac{1}{2}x + \dfrac{1}{2}y + \left( { - xy} \right)$
$ \Rightarrow \dfrac{1}{2}x + \dfrac{1}{2}y + \left( { - 1} \right)xy$
As, we know that coefficients are the values that are with the variable, leaving the variable part all the remaining values are coefficients.For, example in the given equation above for the operand $ - xy$ as expressed $ + \left( { - xy} \right) = + \left( { - 1} \right)xy$, leaving the variables $xy$ we have the coefficient $\left( { - 1} \right)$.
Similarly, for other operands we have, the coefficients as: for $x$ in $\dfrac{1}{2}x$, the coefficient is $\dfrac{1}{2}$. And the coefficient of $y$ in $\dfrac{1}{2}y$, the coefficient is $\dfrac{1}{2}$.
Therefore, we can write:
Coefficient of $x$ in the term $\dfrac{x}{2}$ is $\dfrac{1}{2}$
Coefficient of $y$ in the term $\dfrac{y}{2}$ is $\dfrac{1}{2}$
Coefficient of $xy$ in the term $ - xy$ is $ - 1$.
Hence, option D is correct.
Note: Constants are the terms whose values are never changed. For example, 2, 4, 6, … are constants. Variables are the values that are changed for every constant value. It can be expressed by any alphabet like x, y, z, a, b, w, etc.
Complete step by step solution:
We are given with an equation $\dfrac{x}{2} + \dfrac{y}{2} - xy$. Separating the variables and constants from each operand, we can write the equation as:
$\dfrac{x}{2} + \dfrac{y}{2} - xy$
$ \Rightarrow \dfrac{1}{2}x + \dfrac{1}{2}y - xy$ ……(1)
And, for the last operand we know that $ - x$ can be written as $\left( { - 1} \right)x$.
So, we can write the last operand $ - xy$ as $ + \left( { - xy} \right) = + \left( { - 1} \right)xy$.
Substituting this value in the equation 1, we get:
$ \Rightarrow \dfrac{1}{2}x + \dfrac{1}{2}y + \left( { - xy} \right)$
$ \Rightarrow \dfrac{1}{2}x + \dfrac{1}{2}y + \left( { - 1} \right)xy$
As, we know that coefficients are the values that are with the variable, leaving the variable part all the remaining values are coefficients.For, example in the given equation above for the operand $ - xy$ as expressed $ + \left( { - xy} \right) = + \left( { - 1} \right)xy$, leaving the variables $xy$ we have the coefficient $\left( { - 1} \right)$.
Similarly, for other operands we have, the coefficients as: for $x$ in $\dfrac{1}{2}x$, the coefficient is $\dfrac{1}{2}$. And the coefficient of $y$ in $\dfrac{1}{2}y$, the coefficient is $\dfrac{1}{2}$.
Therefore, we can write:
Coefficient of $x$ in the term $\dfrac{x}{2}$ is $\dfrac{1}{2}$
Coefficient of $y$ in the term $\dfrac{y}{2}$ is $\dfrac{1}{2}$
Coefficient of $xy$ in the term $ - xy$ is $ - 1$.
Hence, option D is correct.
Note: Constants are the terms whose values are never changed. For example, 2, 4, 6, … are constants. Variables are the values that are changed for every constant value. It can be expressed by any alphabet like x, y, z, a, b, w, etc.
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