
Identify the correct descending order of equivalent weights:
I) \[{\text{Ag}}\]
II) \[{\text{H}}\]
III) \[{\text{Cu}}\]
IV) \[{\text{Zn}}\]
A. I, IV, III, II
B.I,III,IV,II
C.I,II,IV,III
D.IV,II,III,I
Answer
570.9k+ views
Hint: The equivalent weight of a solution is given as the molecular weight of the solute that is divided by the valency of the solute. Equivalent weight is used for calculating the mass of a substance in laboratory analysis, mostly titration.
Complete step by step answer:
We know that the formula of equivalent weight is given as,
\[\therefore {\text{Equivalent}}\,{\text{weight}}\, = \,\dfrac{{{\text{M}}{\text{.W}}}}{{{\text{N}} - \,{\text{factor}}}}\]
Here, \[{\text{M}}{\text{.W}}\]= molecular weight
\[{\text{N - Factor}}\]= valency factor.
Now, we will calculate the equivalent weight of \[{\text{Ag}}\],\[{\text{H}}\],\[{\text{Cu}}\]and \[{\text{Zn}}\].
We know that valency of silver is +1 and molecular weight is 108.
So, equivalent weight of\[{\text{Ag}} = \,\dfrac{{108}}{1} = 108\]
We know that valency of zinc is +2 and molecular weight is 66.
So, equivalent weight of \[{\text{Zn}} = \dfrac{{66}}{2} = \,33\]
We know that valency of copper is +2 and molecular weight is 64
So, equivalent weight of \[{\text{Cu}} = \dfrac{{64}}{2} = \,32\]
We know that valency of hydrogen is +1 and molecular weight is 1.
So, equivalent weight of \[{\text{H}}\, = \,\dfrac{1}{2} = \,0.5\]
Therefore, the correct descending order of equivalent weights is \[{\text{Ag}}\,{\text{ > }}\,{\text{Zn}}\,{\text{ > }}\,{\text{Cu > }}\,{\text{H}}\]
So, the correct answer is Option A .
Note:
Students may get confused between molecular weight and equivalent weight. The molecular weight of a compound is calculated by adding the molar masses of all the constituent atoms. It is the mass of an element divided by the amount of the given substance. Equivalent weight is calculated by dividing the molecular weight by that of the valency.
Complete step by step answer:
We know that the formula of equivalent weight is given as,
\[\therefore {\text{Equivalent}}\,{\text{weight}}\, = \,\dfrac{{{\text{M}}{\text{.W}}}}{{{\text{N}} - \,{\text{factor}}}}\]
Here, \[{\text{M}}{\text{.W}}\]= molecular weight
\[{\text{N - Factor}}\]= valency factor.
Now, we will calculate the equivalent weight of \[{\text{Ag}}\],\[{\text{H}}\],\[{\text{Cu}}\]and \[{\text{Zn}}\].
We know that valency of silver is +1 and molecular weight is 108.
So, equivalent weight of\[{\text{Ag}} = \,\dfrac{{108}}{1} = 108\]
We know that valency of zinc is +2 and molecular weight is 66.
So, equivalent weight of \[{\text{Zn}} = \dfrac{{66}}{2} = \,33\]
We know that valency of copper is +2 and molecular weight is 64
So, equivalent weight of \[{\text{Cu}} = \dfrac{{64}}{2} = \,32\]
We know that valency of hydrogen is +1 and molecular weight is 1.
So, equivalent weight of \[{\text{H}}\, = \,\dfrac{1}{2} = \,0.5\]
Therefore, the correct descending order of equivalent weights is \[{\text{Ag}}\,{\text{ > }}\,{\text{Zn}}\,{\text{ > }}\,{\text{Cu > }}\,{\text{H}}\]
So, the correct answer is Option A .
Note:
Students may get confused between molecular weight and equivalent weight. The molecular weight of a compound is calculated by adding the molar masses of all the constituent atoms. It is the mass of an element divided by the amount of the given substance. Equivalent weight is calculated by dividing the molecular weight by that of the valency.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

