
Hydrogen peroxide acts as an oxidising and as a reducing agent, depending upon the nature of the reacting species. In which of the following cases ${ H }_{ 2 }{ O }_{ 2 }$ acts as a reducing agent in acid medium?
(A) ${ MnO }_{ 4 }^{ - }$
(B) ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$
(C) ${ SO }_{ 3 }^{ 2- }$
(D) $KI$
Answer
558.3k+ views
Hint: In redox reactions, one species is oxidised while the other gets reduced. Not all chemical species can oxidise or reduce each other. Whether it will be oxidised or reduced by another species depends upon their redox potential which is a measure of the tendency of a species to accept or donate electrons to an electrode (generally the Standard hydrogen electrode) and thus be reduced or oxidised respectively.
Complete step by step solution:
Before solving this question, we need to understand the meaning of a redox reaction. In redox reactions, one species is oxidised while the other gets reduced. Not all chemical species can oxidise or reduce each other. Whether it will be oxidised or reduced by another species depends upon their redox potential which is a measure of the tendency of a species to accept or donate electrons to an electrode (generally the Standard hydrogen electrode) and thus be reduced or oxidised respectively.
An oxidising agent will itself get reduced by accepting electrons thereby oxidising the other species. A reducing agent gets itself oxidised by donating electrons thereby reducing the other species. If we have two species that can undergo redox reaction, then the species with greater redox potential will get reduced since it will have a greater tendency to get reduced as is indicated by its greater redox potential. It will accept electrons from the other species; itself getting reduced while oxidising the other species. The redox potential for a particular species also depends upon the medium of the reaction i.e. whether the reaction is carried out in acidic medium, basic medium or in neutral medium. Hence the value of the redox potential for a particular species will be different depending on whether the reaction is carried out in acidic, basic or neutral medium. Also, if for a redox reaction, its total redox potential comes out to be positive then the reaction is feasible.
Now, the standard reduction potential for ${ H }_{ 2 }{ O }_{ 2 }$ in acidic medium is 1.763 V while its oxidation potential is -0.682 V. The standard reduction potential for ${ MnO }_{ 4 }^{ - }$ in acidic medium is 1.49 V. The standard reduction potential for ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$ in acidic medium is 1.33 V. ${ SO }_{ 3 }^{ 2- }$ ion is already reduced, hence it will not get reduced by ${ H }_{ 2 }{ O }_{ 2 }$. Similarly in KI, the iodide ion is already reduced, hence it will not get reduced by ${ H }_{ 2 }{ O }_{ 2 }$. The reduction potential of ${ K }^{ + }$ ion in acidic medium is -2.925 V.
From all these values we come to the conclusion that the redox potential for the reaction involving the oxidation of ${ H }_{ 2 }{ O }_{ 2 }$ and reduction of ${ MnO }_{ 4 }^{ - }$ is 0.808 V. Similarly the redox potential for the reaction involving the oxidation of ${ H }_{ 2 }{ O }_{ 2 }$ and reduction of ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$ is 0.648 V. Hence ${ H }_{ 2 }{ O }_{ 2 }$ will act as a stronger reducing agent with ${ MnO }_{ 4 }^{ - }$ than with ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$ (although both reactions are feasible).
Hence the correct answer is (A) ${ MnO }_{ 4 }^{ - }$.
Note: The redox potentials are actually the reduction potentials of the species and not the oxidation potentials so if the redox potential of a species is given, it is actually its reduction potential. Also if the redox potential of a species is more negative than the other, then the former has a less tendency to get reduced and the latter has a more tendency to get reduced.
Complete step by step solution:
Before solving this question, we need to understand the meaning of a redox reaction. In redox reactions, one species is oxidised while the other gets reduced. Not all chemical species can oxidise or reduce each other. Whether it will be oxidised or reduced by another species depends upon their redox potential which is a measure of the tendency of a species to accept or donate electrons to an electrode (generally the Standard hydrogen electrode) and thus be reduced or oxidised respectively.
An oxidising agent will itself get reduced by accepting electrons thereby oxidising the other species. A reducing agent gets itself oxidised by donating electrons thereby reducing the other species. If we have two species that can undergo redox reaction, then the species with greater redox potential will get reduced since it will have a greater tendency to get reduced as is indicated by its greater redox potential. It will accept electrons from the other species; itself getting reduced while oxidising the other species. The redox potential for a particular species also depends upon the medium of the reaction i.e. whether the reaction is carried out in acidic medium, basic medium or in neutral medium. Hence the value of the redox potential for a particular species will be different depending on whether the reaction is carried out in acidic, basic or neutral medium. Also, if for a redox reaction, its total redox potential comes out to be positive then the reaction is feasible.
Now, the standard reduction potential for ${ H }_{ 2 }{ O }_{ 2 }$ in acidic medium is 1.763 V while its oxidation potential is -0.682 V. The standard reduction potential for ${ MnO }_{ 4 }^{ - }$ in acidic medium is 1.49 V. The standard reduction potential for ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$ in acidic medium is 1.33 V. ${ SO }_{ 3 }^{ 2- }$ ion is already reduced, hence it will not get reduced by ${ H }_{ 2 }{ O }_{ 2 }$. Similarly in KI, the iodide ion is already reduced, hence it will not get reduced by ${ H }_{ 2 }{ O }_{ 2 }$. The reduction potential of ${ K }^{ + }$ ion in acidic medium is -2.925 V.
From all these values we come to the conclusion that the redox potential for the reaction involving the oxidation of ${ H }_{ 2 }{ O }_{ 2 }$ and reduction of ${ MnO }_{ 4 }^{ - }$ is 0.808 V. Similarly the redox potential for the reaction involving the oxidation of ${ H }_{ 2 }{ O }_{ 2 }$ and reduction of ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$ is 0.648 V. Hence ${ H }_{ 2 }{ O }_{ 2 }$ will act as a stronger reducing agent with ${ MnO }_{ 4 }^{ - }$ than with ${ Cr }_{ 2 }{ O }_{ 7 }^{ 2- }$ (although both reactions are feasible).
Hence the correct answer is (A) ${ MnO }_{ 4 }^{ - }$.
Note: The redox potentials are actually the reduction potentials of the species and not the oxidation potentials so if the redox potential of a species is given, it is actually its reduction potential. Also if the redox potential of a species is more negative than the other, then the former has a less tendency to get reduced and the latter has a more tendency to get reduced.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

