
How do you solve $z + 4(2z + 3) = 15$ ?
Answer
538.5k+ views
Hint: Take out all the like terms to one side and all the alike terms to the other side. Take out all the common terms. Reduce the terms on the both sides until they cannot be reduced any further if possible. Then finally evaluate the value of the unknown variable.
Complete step by step solution:
First we will start off by opening the brackets and taking all the like terms to one side.
\[
z + 4(2z + 3) = 15 \\
z + 8z + 12 = 15 \\
z + 8z = 15 - 12 \\
\]
Now we will take out any common terms from both sides if possible.
$z(1 + 8) = 3(5 - 4)$
Now we will reduce the terms on both the sides.
$z(1 + 8) = 3(5 - 4)$
Now we simplify our final answer that is evaluate the value of the variable $x$.
$\begin{array}{*{20}{c}}
{z(1 + 8)}& = &{3(5 - 4)}&{} \\
{\,\,\,z(9)}& = &{3(1)}&{} \\
{3z}& = &1&{} \\
z& = &{\dfrac{1}{3}}&{}
\end{array}$
Hence, the value of $z$ is $\dfrac{1}{3}$.
Additional Information: To cross multiply terms, you will multiply the numerator in the first fraction times the denominator in the second fraction, then you write that number down. Then you multiply the numerator of the second fraction times the number in the denominator of your first fraction, and then you write that number down. By Cross multiplication of fractions, we get to know if two fractions are equal or which one is greater. This is especially useful when you are working with larger fractions that you are not sure how to reduce. Cross multiplication also helps us to solve for unknown variables in fractions.
Note: While cross multiplying the terms, multiply the terms step-by-step to avoid any mistakes. After cross multiplication, take the variables to a side and integer type of terms to the other side. Reduce the terms by factorisation.
Complete step by step solution:
First we will start off by opening the brackets and taking all the like terms to one side.
\[
z + 4(2z + 3) = 15 \\
z + 8z + 12 = 15 \\
z + 8z = 15 - 12 \\
\]
Now we will take out any common terms from both sides if possible.
$z(1 + 8) = 3(5 - 4)$
Now we will reduce the terms on both the sides.
$z(1 + 8) = 3(5 - 4)$
Now we simplify our final answer that is evaluate the value of the variable $x$.
$\begin{array}{*{20}{c}}
{z(1 + 8)}& = &{3(5 - 4)}&{} \\
{\,\,\,z(9)}& = &{3(1)}&{} \\
{3z}& = &1&{} \\
z& = &{\dfrac{1}{3}}&{}
\end{array}$
Hence, the value of $z$ is $\dfrac{1}{3}$.
Additional Information: To cross multiply terms, you will multiply the numerator in the first fraction times the denominator in the second fraction, then you write that number down. Then you multiply the numerator of the second fraction times the number in the denominator of your first fraction, and then you write that number down. By Cross multiplication of fractions, we get to know if two fractions are equal or which one is greater. This is especially useful when you are working with larger fractions that you are not sure how to reduce. Cross multiplication also helps us to solve for unknown variables in fractions.
Note: While cross multiplying the terms, multiply the terms step-by-step to avoid any mistakes. After cross multiplication, take the variables to a side and integer type of terms to the other side. Reduce the terms by factorisation.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

