How do you solve for c in ab + c = 5?
Answer
579.6k+ views
Hint: To solve the above question we will use the concept of algebraic equation. We can see from the question that we have to find the value of ‘c’ so we will treat ‘c’ as a variable and ‘ab’ as a constant. Then, we will subtract ‘ab’ from both the side of the above equation and simplify it to get the required value of c.
Complete step-by-step solution:
We will use the concept of algebraic equations to solve the above question. We can see from the question that there are three unknown terms a, b, and c and we have to find the value of c so here we will treat c as a variable and a, b as a constant.
Since, we know from the question that ab + c = 5 and since we are taking a and b as a constant so we can say that ab is also a constant.
So, to find the value of c we will subtract ‘ab’ from both sides of the above equation.
$\begin{align}
& \Rightarrow ab+c=5 \\
& \Rightarrow ab+c-ab=5-ab \\
& \Rightarrow c=5-ab \\
\end{align}$
Hence, the value of c is $( 5 - ab)$.
This is our required solution.
Note: When we are given an algebraic equation which has more than two different variable and we have to find the value of one of the variable and no any other equation or information is known expect a given equation then we always treat one of the unknown as variable and rest other as constants.
Complete step-by-step solution:
We will use the concept of algebraic equations to solve the above question. We can see from the question that there are three unknown terms a, b, and c and we have to find the value of c so here we will treat c as a variable and a, b as a constant.
Since, we know from the question that ab + c = 5 and since we are taking a and b as a constant so we can say that ab is also a constant.
So, to find the value of c we will subtract ‘ab’ from both sides of the above equation.
$\begin{align}
& \Rightarrow ab+c=5 \\
& \Rightarrow ab+c-ab=5-ab \\
& \Rightarrow c=5-ab \\
\end{align}$
Hence, the value of c is $( 5 - ab)$.
This is our required solution.
Note: When we are given an algebraic equation which has more than two different variable and we have to find the value of one of the variable and no any other equation or information is known expect a given equation then we always treat one of the unknown as variable and rest other as constants.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
Convert 200 Million dollars in rupees class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE

How many thousands make a crore class 7 maths CBSE

What is a subcontinent class 7 social science CBSE

How many crores make 10 million class 7 maths CBSE


