Answer
385.8k+ views
Hint: In the given problem we need to solve this for ‘x’. We can solve this using the transposition method. The common transposition method is to do the same thing (mathematically) to both sides of the equation, with the aim of bringing like terms together and isolating the variable (or the unknown quantity).
Complete step-by-step solution:
Given \[\dfrac{x}{2} = - 10\].
Here we need the value of ‘x’.
Since the unknown variable is in the left hand side of the equation, we transpose all the numbers to the right hand side of the equation.
We transpose 2 to the right hand side of the equation by multiplying ‘2’ on the right hand side of the equation.
\[ \Rightarrow x = - 10 \times 2\]
We also know that the product of the negative number and the positive number results in giving the negative number.
\[ \Rightarrow x = - 20\]
Note: We can check whether the obtained answer is correct or not. All we need to do is substitute the obtained value in the given problem.
\[\dfrac{{ - 20}}{2} = - 10\]
\[ \Rightarrow - 10 = - 10\]. Hence the obtained answer is correct.
Note: We can check whether the obtained answer is correct or not. All we need to do is substitute the obtained value in the given problem.
\[\dfrac{{ - 20}}{2} = - 10\]
\[ \Rightarrow - 10 = - 10\].
Hence the obtained answer is correct.
We want to transpose the addition number to any side of the equation. We subtract it with the same number on both sides of the equation. Similarly if we want to transpose the negative number to any side of the equation we add with the same number on both sides of the equation. Similarly if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Complete step-by-step solution:
Given \[\dfrac{x}{2} = - 10\].
Here we need the value of ‘x’.
Since the unknown variable is in the left hand side of the equation, we transpose all the numbers to the right hand side of the equation.
We transpose 2 to the right hand side of the equation by multiplying ‘2’ on the right hand side of the equation.
\[ \Rightarrow x = - 10 \times 2\]
We also know that the product of the negative number and the positive number results in giving the negative number.
\[ \Rightarrow x = - 20\]
Note: We can check whether the obtained answer is correct or not. All we need to do is substitute the obtained value in the given problem.
\[\dfrac{{ - 20}}{2} = - 10\]
\[ \Rightarrow - 10 = - 10\]. Hence the obtained answer is correct.
Note: We can check whether the obtained answer is correct or not. All we need to do is substitute the obtained value in the given problem.
\[\dfrac{{ - 20}}{2} = - 10\]
\[ \Rightarrow - 10 = - 10\].
Hence the obtained answer is correct.
We want to transpose the addition number to any side of the equation. We subtract it with the same number on both sides of the equation. Similarly if we want to transpose the negative number to any side of the equation we add with the same number on both sides of the equation. Similarly if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)