How do you solve \[4h + 6 = 30\] ?
Answer
576.9k+ views
Hint: We can first reorder the terms according to the question. After that we can solve the question for the variable \[h\]. We can group the like terms on one side so that it will be easier to solve. Then after forming the easier equation, we can simplify it, and we will get our answer.
Complete step by step solution:
According to the question, our equation is:
\[4h + 6 = 30\]
We will first reorder the terms for easy solving.
\[ \Rightarrow 6 + 4h = 30\]
Then we will solve for the variable \[h\]. We need to add \[ - 6\] in both the parts of the equation. We do this to cancel out the terms from left so that we can solve the equation for the variable \[h\] and get the answer:
\[ \Rightarrow 6 + ( - 6) + 4h = 30 + ( - 6)\]
When we simplify this, we get:
\[ \Rightarrow 6 - 6 + 4h = 30 - 6\]
\[ \Rightarrow 0 + 4h = 24\]
\[ \Rightarrow 4h = 24\]
Now, we have to divide \[4\]to both the terms. This is done to make the variable \[h\] alone. By dividing the terms by \[4\], we get:
\[ \Rightarrow \dfrac{{4h}}{4} = \dfrac{{24}}{4}\]
Here, the numbers which are divisible or are common get cancelled. The \[4\] on the numerator and the denominator gets cancelled from the left side. The number \[24\] gets cancelled from \[4\] leaving a remainder of \[6\], and then we get our answer as:
\[ \therefore h = 6\]
Our final answer here is \[h = 6\].
Note: The above method is very easy and the question is solved very quickly. But we have another method also. We can make the variable \[h\] alone by shifting \[6\]t o the other side. On that side \[6\] gets subtracted from \[30\] and the result is \[24\], and then shifts \[4\] also to the other side. The number \[4\] gets divided with a result that is \[24\] and the final answer is \[6\]. This method is also easy to solve.
Complete step by step solution:
According to the question, our equation is:
\[4h + 6 = 30\]
We will first reorder the terms for easy solving.
\[ \Rightarrow 6 + 4h = 30\]
Then we will solve for the variable \[h\]. We need to add \[ - 6\] in both the parts of the equation. We do this to cancel out the terms from left so that we can solve the equation for the variable \[h\] and get the answer:
\[ \Rightarrow 6 + ( - 6) + 4h = 30 + ( - 6)\]
When we simplify this, we get:
\[ \Rightarrow 6 - 6 + 4h = 30 - 6\]
\[ \Rightarrow 0 + 4h = 24\]
\[ \Rightarrow 4h = 24\]
Now, we have to divide \[4\]to both the terms. This is done to make the variable \[h\] alone. By dividing the terms by \[4\], we get:
\[ \Rightarrow \dfrac{{4h}}{4} = \dfrac{{24}}{4}\]
Here, the numbers which are divisible or are common get cancelled. The \[4\] on the numerator and the denominator gets cancelled from the left side. The number \[24\] gets cancelled from \[4\] leaving a remainder of \[6\], and then we get our answer as:
\[ \therefore h = 6\]
Our final answer here is \[h = 6\].
Note: The above method is very easy and the question is solved very quickly. But we have another method also. We can make the variable \[h\] alone by shifting \[6\]t o the other side. On that side \[6\] gets subtracted from \[30\] and the result is \[24\], and then shifts \[4\] also to the other side. The number \[4\] gets divided with a result that is \[24\] and the final answer is \[6\]. This method is also easy to solve.
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